The mass of nitrogen gas that participated in the chemical reaction is 1.54g
HOW TO CALCULATE MASS OF AN ELEMENT:
- Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;
- mass (M) = molar mass (MM) × number of moles (n)
According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.
- The molecular mass of nitrogen gas (N2) = 14.01(2)
= 28.02g/mol
Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:
- Mass (g) = 0.0550 mol × 28.02 g/mol
Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g
Learn more: brainly.com/question/18269198
Answer:
5.3 × 10⁻¹⁷ mol·L⁻¹
Explanation:
Let <em>s</em> = the molar solubility.
Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq); K_{sp} = 6.1 × 10⁻⁴⁹
E/mol·L⁻¹: 2<em>s</em> <em>s
</em>
K_{sp} =[Cu⁺]²[S²⁻] = (2<em>s</em>)²×<em>s</em> = 4s^3 = 6.1 × 10⁻⁴⁹

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Answer:
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Answer:
Salts can be several different colors and may be any of the five tastes, including salty, sweet, bitter, sour or savory. Their odor depends on the acid and base it is comprised of. Salts comprised of strong acids and bases, called strong salts, are odorless.
A slice of pizza is an example of a Heterogeneous mixture.