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viva [34]
2 years ago
12

If 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction

Chemistry
1 answer:
RideAnS [48]2 years ago
5 0

0.1 moles of chloride ions were involved  in the reaction if 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction.

Explanation:

Data given:

volume of CaCl_{2} = 25 ml 0r 0.025

molarity of the calcium chloride solution = 2M

number of chloride ions =?

Balance chemical reaction:

Ca + 2Cl_{2} ⇒Ca_{} Cl_{2}

number of moles in 25 ml is calculated as:

molarity = \frac{number of moles}{volume}

number of moles of calcium chloride  = molarity x volume

putting the values in the equation:

number of moles = 2 x 0.025

                            = 0.05 moles of calcium chloride

1 mole of  CaCl_{2}  decomposes as 1 calcium ion and 2 chloride ions

so 0.05 moles will have x moles of chloride ion

\frac{2}{1} = \frac{x}{0.05}

x= 0.1

0.1 moles of chloride ions will be involved in the reaction.

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An intravenous infusion is to contain 15 mEq of potassium ion and 20 mEq of sodium ion in 500 mL of 5% dextrose injection. Using
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Answer:

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