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3 years ago

Jody can swim one length of the pool in 3 4ths of a minute.how long will it take jody to swim six lengths of the pool

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

4 0

I believe that it is eight minutes

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Use distributive property to simplify 5(s-5t)

Fofino [41]

<span>5(s-5t) =5s -25t ...</span><span>distributive property

hope it helps</span>

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4 years ago

Read 2 more answers

Tamir bought 2 1/2 pounds of fish at $5.50 per pound, and two bananas at $0.45 each.

tia_tia [17]

0.45+0.45= $0.90 + 5.50x2+2.25=$13.25 13.25+0.90 =$14.50 he would get $5.50 back out of the 20$ spent

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3 years ago

Rewrite the equation -30x + 2y- 100=0

Black_prince [1.1K]

Rewritten: y=15x + 50
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y intercept: (0,50)

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3 years ago

Please help me, I’m not that smart!

Oxana [17]

Answer:

$\frac{16 {d}^{3} }{ {c}^{2} }$

Step-by-step explanation:

${4}^{2} {c}^{ - 2} {d}^{3} {e}^{0}$

➡️ $16 {c}^{ - 2} {d}^{3} \times 1$

➡️ $16 {c}^{ - 2} {d}^{3}$

➡️ $16 \times \frac{1}{ {c}^{2} } \times {d}^{3}$

➡️ $\frac{16 {d}^{3} }{ {c}^{2} }$

8 0

3 years ago

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$

7 0

2 years ago