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nignag [31]
3 years ago
5

When adding two fractions do i leave the denominator how it is?

Mathematics
1 answer:
telo118 [61]3 years ago
7 0
Hoi!

If the two fractions have a common denominator, then yes, you do. Only add the numerators. :)
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Which expression represents four less than half a number, n? (show your work)
ikadub [295]
The answer is 1/2n-4

Multiplying a number n by 1/2 is the same as dividing that number by 2.
5 0
2 years ago
Read 2 more answers
Find the first three iterates of the function f(z)=z2+c with a value of c=1+2i and an initial value of z0=0
aalyn [17]

Answer:

14x

Step-by-step explanation:

multiply the 2i by the 0 eulogistic quotient

7 0
3 years ago
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Berry Delicious is a popular shop that sells chocolate-covered strawberries. Last year, the shop used 9,200 kilograms of strawbe
coldgirl [10]

Answer:

15.9%

Step-by-step explanation:

Percent decrease formula =

(Initial value - New value/Initial value) × 100

Initial value = 9200kg

New value = 7739.4kg

Percent decrease = (9200 - 7739.4/9200) × 100

Percent decrease = (1460.6/9200) × 100

Percent decrease = 15.8760869565%

Approximately = 15.9%

The percent of decrease in the amount of strawberries used annually is 15.9%

6 0
3 years ago
The midpoint of y and 31 is -5. what is y
pochemuha
Y = -41.
EXPLANATION.
if -5 is the midpoint, it must be -5 + 36.
Because there is 36 numbers between 31 and -5.
So -5 + 36 = -41.
4 0
3 years ago
Math help what is the answer will give brainliest.
artcher [175]
The two equations are
x + y = 7
and
4x + 2.5y = 22
the first equation can be solved for x to be
x = 7 - y
next you can substitute x in the second equation
4(7 - y) + 2.5y = 22
Distribute 4 to everything in the parentheses
28 - 4y + 2.5y = 22
combine like terms:
28 - 1.5y = 22
subtract 28 from both sides of the equation
- 1.5y =  - 6
divide both sides by -1.5
y =  4
plug this in to the original equation of x+y=7
x + 4 = 7
subtract 4 from both sides.
x = 3
Final Answer: they bought 3 adult tickets and 4 student tickets


Hope this helps!
7 0
3 years ago
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