Decrease £2155.45 by 18.5%
1 answer:
You might be interested in
Answer:
- Area of the rectangle: 24 cm²
- Area of the circle: 380.13 cm²
- Area of between the circle and the rectangle: 356.13 cm²
Explanation:
The question describes<em> a rectangle of dimensions 4 cm × 6 cm inscribed in a circle with radius 11 cm</em>.
You can find:
- The area of the rectangle
- The area of the circle
- The area between the rectangle and the circle.
<u>1. Area of the rectangle:</u>
<u>2. Area of the circle:</u>
<u>3. Area between the rectangle of the circle:</u>
This is the area of the circle that does not belong to (or is outside of) the area of the rectangle.
Answer:
The answer to your question is below
Step-by-step explanation:
Data
Equation 25x² + 64y² = 1600
Process
1.- Divide all the equation by 1600
25x²/1600 + 64y²/ 1600 = 1600/1600
-Simplify
x²/64 + y²/ 25 = 1
2.- Equation of a horizontal ellipse
3.- Find a, b and c
a² = 64 a = 8
b² = 25 b = 5
-Calculate c with the Pythagorean theorem
a² = b² + c²
-Solve for c
c² = a² - b²
-Substitution
c² = 8² - 5²
-Simplification
c² = 64 - 25
c² = 39
-Result
c = √13
4.- Find the center
C = (0, 0)
5.- Find the vertices
V1 = (-8, 0) V2 = (8, 0)
6.- Find the foci
F1 = (-√13, 0) F2 = (√13, 0)