9514 1404 393
Answer:
- Keiko: 17
- Chang: 24
- Abdul: 68
Step-by-step explanation:
Let c represent the number of messages sent by Chang. Then Keiko sent (c-7) messages, and Abdul sent 4(c-7) messages. The total number sent was ...
c + (c -7) +4(c -7) = 109
6c -35 = 109 . . . . . . . . . . simplify
6c = 144 . . . . . . . . . . . add 35
c = 24 . . . . . . . . . . . divide by 6
c-7 = 17
4(c-7) = 68
Keiko sent 17, Chang sent 24, and Abdul sent 68 text messages.
Answer:
The estimated weight is in the range:
75.6 pounds 
Weight 92.4 pounds
Step-by-step explanation:
Since, the maximum error is 10%.
Therefore, the maximum and minimum vales will be 10% more and 10% less than 84 pounds, respectively.
<u>For Maximum Limit</u>:
= (1.1)(84 pounds)
= <u>92.4 pounds</u>
<u>For Minimum Limit</u>:
= (0.9)(84 pounds)
= <u>75.6 pounds</u>
Hence, the estimated weight is in the range:
75.6 pounds Weight 92.4 pounds
Let us take a number x
The four consecutive numbers will be
x+1, x+2, x+3
Thus our equation will be
x + x+1 + x+2 + x+3 = 42
4x + 6 = 42
4x = 36
x= 36/4
x= 9
Thus the four numbers are (substitute)
x=9
x+1=9+1=10
x+2=9+2=11
x+3=9+3=12
9,10,11,12
(3,59)(5,87)
slope = (87 - 59) / (5 - 3) = 28/2 = 14 <== ur slope
y = mx + b
slope(m) = 14
use either of ur points...(3,59)...x = 3 and y = 59
now we sub and find b, the y int
59 = 14(3) + b
59 = 42 + b
59 - 42 = b
17 = b <=== ur y int (0,17)
