The number of tickets that should be purchased for the cost of both carnival to be equal is 10 tickets.
Assume the number of tickets to be purchased is x.
The expression for the total cost at Carnival M is:
= Entrance fee + (price of tickets x number of tickets)
= 5 + 0.50x
The expression for the total cost at Carnival P is:
= 7 + 0.30x
To find the number of tickers, equate both expressions:
5 + 0.50x = 7 + 0.30x
0.50x - 0.30x = 7 - 5
0.20x = 2
x = 2 / 0.20
= 10 tickets
10 tickets will need to be bought to both Carnivals for the cost to be the same.
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Some are
y-2=-3x
y+3x=2
3x=2-y
The possible lengths of the garden would be all of the common factors of 1200.
1 , 1200
2 , 600
3 , 400
4 , 300
5 , 240
6 , 200
7 , 171.43
8 , 150
9 , 133.33
10 . 120
11 . 109.09
12. 100
13. 92.31
14. 85.71
15. 80
16. 75
17. 70.59
18. 66.67
19. 63.15
20. 60
And so on. (all of the above are in pairs)
X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
Step-by-step explanation:
The hole never disappears; at the end of the story, the first things that went into the hole come out of the sky and back into the city. There's no sign that the hole is gone
