Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,

Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 %
</u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>
1. The conjugate acid-base pairs are HCl/Cl- and NH3/NH4+. They can be changed into one another by proton transfer.
2. The acid in the reaction is the molecule that has the lowest pKa value or (simply) gives their proton away the easiest. The pKa of HCl is around 3 I think while ammonia’s is around 35. This means HCl is the acid here. In the other reaction (backwards) you can see that NH4+ gives a proton to the chloride ion. To give a proton = acid. So the acids are HCl and NH4+ and the bases are NH3 and Cl-.
An important rule is: The stronger the acid/base, the weaker its conjugate base/acid.
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The reaction CO₂(g) → C(s) +O₂(g) is a decomposition reaction is true
Explanation
A Decomposition reaction is a reaction in which involve breaking down a compound into two or more simpler substances.
The reaction above is a decomposition reaction since CO₂ molecule is broken down into C (an element) and O₂ (a molecule).
3.815 that's the awnser......................................