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Fofino [41]
3 years ago
10

A biochemist is attempting to replicate a chemical reaction that commonly takes place in cells. during the chemical reaction, st

arch is broken down into glucose. what will most likely happen if the amount of enzyme that catalyzes this reaction is increased?
a. the reaction will slow down.
b. the reaction will stop.
c. the reaction will speed up.
d. the reaction will take place at a higher temperature.
Chemistry
1 answer:
BartSMP [9]3 years ago
4 0
If the concentration of enzyme increases, then reaction should speed up (answer C).
enzyme speeds up a chemical reaction by lowering activation energy to provide an alternative pathway of reaction mechanism. assuming that enzyme which usually is the limiting factor, the increase of enzyme concentration should lead to more product formation i.e. maltose from the breakdown of starch.
the enzyme discussed here should be amylase.

higher temperature beyond optimum value enzyme found in our human body will usually least to denaturation of active site of enzyme. hence lead to loss of enzyme activity permanently.
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The principal component of mothballs is naphthalene, a compound with a molecular mass of about 130 amu, containing only carbon a
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Answer:

Empirical formula = C5H4

Molecular formula = C10H8

Explanation:

When the 3000 mg of naphthalene are burned they produce 10.3 mg of CO2. Knowing the unbalanced equation of the combustion of naphthalene, we have:

CxHy + O2 = CO2 + H2O

We calculate the molar composition of the sample. We look for the molecular weights in the periodic table:

CO2 = 12,011 + 2 (15,999) = 44,009 g

Mol C = 10.3 mg * (1 mol CO2 / 44.009 g CO2) * (1 mol C / 1 mol CO2) = 0.234 mmol C

Mass C = 0.234 mmol C * (12.011 g C / 1 mol C) = 2.8105 mg C

Mass H = 3 mg - 2.8105 mg = 0.1895 mg H

Mol H = 0.1895 mg H * (1 mol H / 1,008 g H) = 0.188 mmol H

To calculate the empirical formula, we must divide the number of moles of each element by the smallest number of moles, in this case, of hydrogen:

C = 0.2340 mmol C / 0.1895 mol H = 1.25

H = 0.1895 mmol H / 0.1895 mmol H = 1

We multiply the coefficients by 4, and we have the empirical formula:

C1.25 * 4H1 * 4 = C5H4

The molecular formula is equal to (C5H4)m, where m is calculated by the molecular and empirical mass ratio, as follows:

Empirical mass = (5 * 12.011) + (4 * 1.008) = 64.09 g

m = 130 g / 64.09 g = 2.02 = 2

Therefore we have the molecular formula:

(C5H4)2 = C10H8

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The given statement is True.


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