Answer:o
Step-by-step explanation:
Let a = aircraft 1 seats
Let b = aircraft 2 seats
Let c = aircraft 3 seats
From the information given above, let's make basic equations.
![a=51+b](https://tex.z-dn.net/?f=a%3D51%2Bb)
![b=b](https://tex.z-dn.net/?f=%20b%3Db%20)
![c=b-54](https://tex.z-dn.net/?f=c%3Db-54)
![a+b+c=411](https://tex.z-dn.net/?f=a%2Bb%2Bc%3D411)
We can begin to plug in values we know.
![51+b+b+b-54=411](https://tex.z-dn.net/?f=%2051%2Bb%2Bb%2Bb-54%3D411%20)
![3b-3=411](https://tex.z-dn.net/?f=3b-3%3D411)
![3b=414](https://tex.z-dn.net/?f=3b%3D414)
![b=138](https://tex.z-dn.net/?f=b%3D138)
We now know that the second aircraft has 138 seats. Now we can plug in this value to find the value of the other seats. Let's start with the first aircraft.
![a=51+b](https://tex.z-dn.net/?f=a%3D51%2Bb)
![a=51+138](https://tex.z-dn.net/?f=a%3D51%2B138)
![a=189](https://tex.z-dn.net/?f=a%3D189)
We now know that the first aircraft has 189 seats. Let's now finally solve for the third aircraft.
![c=b-54](https://tex.z-dn.net/?f=c%3Db-54)
![c=138-54](https://tex.z-dn.net/?f=c%3D138-54)
![c=84](https://tex.z-dn.net/?f=c%3D84)
Finally, we know that aircraft 3 has 84 seats. To check our work, let's make sure that each of these values add up to 411.
![a+b+c=411](https://tex.z-dn.net/?f=a%2Bb%2Bc%3D411)
![189+138+84=411](https://tex.z-dn.net/?f=189%2B138%2B84%3D411)
![411=411](https://tex.z-dn.net/?f=%20411%3D411%20)
This is true, therefore the values are correct.
Aircraft 1: 189 seats
Aircraft 2: 138 seats
Aircraft 3: 84 seats
the missing number should be the square root of the last number times 2 for a perfect trinomial
so square root of 49 = 7
7*2 =14
so the missing number should be 14
Answer:
commutative property of addition states that when two numbers are being added, their order can be changed .
Step-by-step explanation:
The answer is y=3 I believe