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salantis [7]
3 years ago
12

This is display behavior that certain animal species use to attract a mate for reproduction.

Biology
1 answer:
elixir [45]3 years ago
5 0
I believe the term you are referring to is "Courtship Behavior", also known as "Courtship Display."

Hope this helped!  :V

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This ocean zone is found on the ocean bottom and includes the ocean floor and the sediments that have settled on the bottom
kumpel [21]

Answer: sea floor (at the very bottom of the ocean)

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3 years ago
An operon is controlled by a repressor. When the repressor binds to a small molecule, it binds to DNA near the operon. The opero
larisa [96]

Answer:

Negatively repressible.

Explanation:

A control which occurs through repressor is known as negative control which may be inducible or repressible.

When a small molecule named as allolactose binds this repressor it leads to allosteric repulsion which removes repressor from the operator as a result of which RNA polymerase can start transcription. Allolactose is therefore known as inducer because it induces lac operon expression.

But here, the operator is active (induced) already so there is no need to induce the operon which means that it can only be repressed so that transcription could stop. So the answer is negatively repressible operon.

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3 years ago
What type of reproduction is most likely taking place?
Vinvika [58]
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3 years ago
If you need to perform hand hygiene and do not have access to running water, using your personal anti-bacterial lotion is suffic
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8 0
4 years ago
Read 2 more answers
Wood deposits recovered from an archaeological site contain 36% of the C-14 they originally contained. How long ago did the tree
Veseljchak [2.6K]

Answer: It was obtained 8515 years ago

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) to find the rate constant:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{5760}=0.00012years^{-1}

b) for completion of 36% of reaction

t=\frac{2.303}{k}\log\frac{100}{36}

t=\frac{2.303}{0.00012}\log\frac{100}{36}

t = 8515 years

The time was 8515 years.

3 0
3 years ago
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