Answer:
Option C: sodium and potassium
Explanation:
Elements in same group having same properties. In given option Only C is the correct option because sodium and potassium are present in same group i.e, group 1 and thus shows similar reactive properties. Bothe are alkali metal and have one valance electron. These are very reactive and can not found in free state in nature but present in compounds.
They react with halogens and form salts.
2Na + Cl₂ → 2NaCl
2K + Cl₂ → 2KCl
All other options are incorrect because,
Option A = Fluorine and neon
Both are present in different group. Fluorine is present in group 17 and neon in group 18 thus their reactivity is not similar.
Option B = Hydrogen and helium
Both are present in different group. Hydrogen is present in group 1 and helium in group 18 thus their reactivity is not similar.
Option D: Aluminum and chlorine
Both are present in different group. Aluminum is present in group 13 and chlorine in group 17 thus their reactivity is not similar.
All these three options are incorrect.
Boiling I think! hope you get it right
<h3>
Answer:</h3>
9,729.73 L
<h3>
Explanation:</h3>
- Based on Boyle's law when temperature is held constant then the volume of a fixed mass of a gas, V is inversely proportional to Pressure, P.
- That is; Pα 1/V
- Mathematically, P= k/V where k is a constant
- Therefore, when the volume of a gas and the pressure are altered,
- P1V1=P2V2 = k, where P1 and P2 are the initial and final pressure respectively while V1 and V2 are the initial and final pressure respectively.
In this case;
Initial Pressure, P1 = 150 atm
Initial volume, V1 = 60.0 L
Final pressure, P2 = 0.925 atm
we are required to calculate the final volume
But, P1V1 =P2V2
Rearranging the formula, V2 = P1V1 ÷ P2
Thus;
V2 =(150 atm × 60.0 L) ÷ 0.925 atm
= 9,729.73 L
The new volume will be 9,729.73 L
<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol
<u>Explanation:</u>
To calculate the molarity of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of triprotic acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.0077 M
Given mass of triprotic acid = 0.188 g
Volume of solution = 250 mL
Putting values in above equation, we get:
Hence, the molar mass of unknown triprotic acid is 97.66 g/mol
Answer:
(a) 3-ethylpentane (because the longest chain is 5 carbon atoms, and ethyl is positioned at the 3rd carbon atom)
(b) 1, 2-dimethylbutane (because two methyl is positioned at the 2nd and 3rd carbon atom)
(c) 3, 4-dimethylhexane (the longest chain here is 6 carbon atoms, and two methyl is positioned at the 3rd and 4rd carbon atom)
(d) 3-methyl 4-ethylhexane ( the longest chain is 6 carbon atoms, one methyl is positioned at the 3rd carbon atom while one ethyl is positioned at the 4rd carbon atom)
(e) and (f) are similar to the question before... and I dunno how to (g) and (h) cuz I haven't learned it
Hope that you are able to answer the rest!!