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Nostrana [21]
3 years ago
11

If 0.500 L of a 4.00-M solution of copper nitrate, Cu(NO3)2, is diluted to a volume of 1.50 L by the addition of water, what is

the molarity of the diluted solution?
Chemistry
1 answer:
Wewaii [24]3 years ago
8 0

Answer:

1.33 M

Explanation:

We'll begin by writing out the data obtained from the question. This includes the following:

Volume of the stock solution (V1) = 0.5L

Molarity of the stock solution (M1) = 4M

Volume of diluted solution (V2) = 1.5L

Molarity of the diluted solution (M2) =.?

With the application of the dilution formula, the molarity of the diluted solution can be obtained as follow:

M1V1 = M2V2

4 x 0.5 = M2 x 1.5

Divide both side by 1.5

M2 = (4 x 0.5) / 1.5

M2 = 1.33 M

Therefore the molarity of the diluted solution is 1.33 M

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Answer:

<u></u>

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Explanation:

Since sulfuric acid, H₂SO₄, is a diprotic acid and potassum hydroxide, KOH, contains one OH⁻ in the formula, the number of moles of potassium hydroxide must be twice the number of moles of sulfuric acid.

<u>1. Determine the number of moles of KOH in 47mL of 0.39M potassium hydroxide solution</u>

  • number of moles = molarity × volume in liters
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<u>2. Determine the number of moles of sulfuric acid needed</u>

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<u>3. Determine the concentration that contains 0.009165 mol in 25mL of the acid.</u>

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  • M = 0.009165mol/(25mL) × (1,000mL/liter) = 0.3666M

Round to two significant figures: 0.37M

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Two posssible lewis structures for the molecule ch2s are given. determine the formal charge on each atom in both structures
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<h3>What is Lewis structure?</h3>

The term Lewis structure is the representation of a compound using its symbols and showing the valence electrons as dots. This question is incomplete as the Lewis structures were not shown.

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