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Nostrana [21]
3 years ago
11

If 0.500 L of a 4.00-M solution of copper nitrate, Cu(NO3)2, is diluted to a volume of 1.50 L by the addition of water, what is

the molarity of the diluted solution?
Chemistry
1 answer:
Wewaii [24]3 years ago
8 0

Answer:

1.33 M

Explanation:

We'll begin by writing out the data obtained from the question. This includes the following:

Volume of the stock solution (V1) = 0.5L

Molarity of the stock solution (M1) = 4M

Volume of diluted solution (V2) = 1.5L

Molarity of the diluted solution (M2) =.?

With the application of the dilution formula, the molarity of the diluted solution can be obtained as follow:

M1V1 = M2V2

4 x 0.5 = M2 x 1.5

Divide both side by 1.5

M2 = (4 x 0.5) / 1.5

M2 = 1.33 M

Therefore the molarity of the diluted solution is 1.33 M

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The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction?
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The formula for mole fraction is:

mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

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1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol

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