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Alex777 [14]
3 years ago
14

Marie Curie's work with radioactive materials eventually lead to her death. At the age of 66, what

Chemistry
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

Radiation-induced Luekimia

Explanation:

They worked with many radioactive elements, so it caused Leukemia which is

a  disease in which the bone marrow and other blood-forming organs produce increased numbers of immature or abnormal leukocytes.

Hoped this helped

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If 840. mL of linseed oil has a mass of 700. g, calculate the density of linseed oil.
aleksklad [387]

Density can be determined as:

d = m /V

whereas, m is mass of compound

v is volume

d = 700 /840 = 0.83 g /mL

Thus density is 0.83 g /mL


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4 years ago
Help? this is a major test. i don’t understand.
m_a_m_a [10]
Mauna kea is the answr
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Why is the inner core's state of matter different from the outer core's state of matter
Ganezh [65]
Because the inner course is a totally different thing then the outer course
3 0
3 years ago
PLEASE HELP!!! Do you think the number of animals that eats plants is related to the number of plants?
mina [271]

Answer:

Yes

Explanation:

As the number of animals that eat plants increase, the number of plants decrease. This is because the animals are eating a larger and larger number of plants and reducing the population.

When the number of plants gets too low, the animals will not be able to survive, and they will start to decrease in numbers. In turn, the plants will increase again. Eventually, they will reach an equilibrium.

4 0
3 years ago
A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
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