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TEA [102]
2 years ago
12

If there is 5 atoms of oxygen in the reactant, how many oxygen atoms must be in the product​

Chemistry
1 answer:
tiny-mole [99]2 years ago
4 0

Answer:

5

Explanation:

It requires 20 chracters to fill this answer

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The most common isotopic forms of hydrogen are ordinary hydrogen (1H) and deuterium (2H), which have percent compositions of 99.
Alborosie

Answer:

0. 000115

Explanation:

A percentage is defined as a ratio with a basis of 100 as total substance. Convert a percentage to decimal implies to divide the percentage in 100 because decimal form has as basis 1.

For the isotopic forms:

1H: 99.98% → As percent.

99.98% / 100 = 0.9998 → As decimal form.

2H: 0.0115% → As percent.

0.0115% / 100 = <em>0. 000115</em>→ As decimal form.

5 0
3 years ago
How many eggs are in 1 mole of eggs?
Pachacha [2.7K]

Answer:

I <em>believe</em> it is Avogadro's number: 6.022 × 10²³

Explanation:

One mole of a substance is equal to 6.022 × 10²³ units of that substance

4 0
2 years ago
Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?
Molodets [167]
It wont melt like gold and copper would at that temperature

4 0
3 years ago
Read 2 more answers
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
2 years ago
The volume of a gas-filled balloon is 30.0 L at 313 K and 1520 mm Hg pressure. What would the volume be at standard temperature
pashok25 [27]
313 k
step-by-step-explanation
4 0
2 years ago
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