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3 years ago

I do not get this

Mathematics

1 answer:

Alex3 years ago

5 0

12x = 2,700
---- ---------
12 12

x = 225

They can make a total of 225 necklaces

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At the beginning of the season, carl had to remove 50 dead orange trees from his farm while each of the remaining trees produced

Len [333]

Answer:

y > (x - 50) * 210

Step-by-step explanation:

Given :

Number of dead trees = 50

Number of oranges produced by each of the remaining trees > 210

Let total number of trees = x ; total number of oranges produced = y

Hence, number of oranges produced, y

y > number of remaining trees * number of oranges produced per tree

y > (x - 50) * 210

7 0

3 years ago

A rectangular flower bed that is 5 ft long and 4 feet wide is surrounded by a square lawn that is

Trava [24]

Answer:

124 ft2

Step-by-step explanation:

The yard is a 12ft square so the length and width would both be 12ft. You multiply the length and width of the yard to get the area of the yard so 12x12=144. You have the length and width of the flower bed so 5x4=20. Once you have the area of both you can subtract the area the flower bed takes up of the lawn. 144-20=124 ft2.

5 0

3 years ago

Solve one third plus seven ninths equals blank

ruslelena [56]

Answer:

10/9ths or 1& 1/9

Step-by-step explanation:

1/3 + 7/9 =

× 9/9. × 3/3

9/27 + 21/27 = 30/27

OR 1 & 1/9

5 0

4 years ago

What are the center and radius of the circle with equation (−)+(−)=?Open x minus 4 close squared . Plus . Open y minus 9 close s

lbvjy [14]

Answer:

Center and radius of the circle of the equation ${(x - 4)^{2} + (y - 9)^{2} = 1$

center = ( 4,9) Radius = 1

Step-by-step explanation:

Given -

Equation of circle is $(x - 4)^{2} + (y - 9)^{2} = 1$

The equation of circle is represented by

$\boldsymbol{\mathbf{(x - a)^{2} + (y - b)^{2} = r^{2}}}$

where a and b are center of circle and radius r

Comparing these equation

then a = 4 and b = 9 and r = 1

3 0

4 years ago

Please solve the answer above correctly showing detailed working

Sergeeva-Olga [200]

<h2>Intersection and Union of Sets</h2><h3>Answer:</h3>

$A \cup B = \{ a, b, c, d, e \}$

$B \cap C = \{ d, e \}$

$A \cup C = \{ a, b, c, d, e, f \}$

<h3>Step-by-step explanation:</h3>

Given:

$A = \{ a, b, c, d \}$

$B = \{ b, d, e \}$

$C = \{ d, e, f \}$

The Union ( $\cup$ ) of sets $A$ and $B$ is just a set containing all the elements of sets $A$ and $B$ . However, elements that are present in both sets should not repeat in the Union of Sets as the elements of a set should distinct be from each other.