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Alona [7]
3 years ago
7

Which expression is equivalent to108--3? O 5/3) O 63 O 73i

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

(A) option

Step-by-step explanation:

becoz according to me when I solved this sum then answer was 5√3

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What is the answer to <br> √a³-7 + -4
Oksanka [162]

Answer:

√a^3−7-4

Step-by-step explanation:

Replace all occurrences of + − with a single −. A plus sign followed by a minus sign has the same mathematical meaning as a single minus sign because 1⋅ −1= −1

4 0
2 years ago
Plz answer correctly and thank you
Alex777 [14]

Answer:

83

Step-by-step explanation:

get rid of decimals and become 2988/36

divide and get 83

7 0
3 years ago
There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?
Verizon [17]
28*4=112
112/8=14 Packages
8 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
What is 697*100 please help
Vedmedyk [2.9K]
Here is a trick I always use:

Get rid of both zeros in100 for now 
So just do 697*1 which is just 697

Now add the two zeros to your answer to get 69,700 which is the final answer
3 0
3 years ago
Read 2 more answers
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