2) A shirt costs $12.50 but there is a discount of 10%. The

A) Is {a, e,i,o,u} a subset of {a,b,c,d,e,f,g,h,i) Why?

kozerog [31]

Answer:

No

Step-by-step explanation:

u and o arent elements of {a, b, c, d, e, f, g, h, i}

8 0

3 years ago

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Match the inequality to the graph of its solution. a. n/4 ≤ -1 b. -10 ≥ -100 c. 5x ≥ 20

postnew [5]

a. n/4 ≤ -1

Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.

That in the real number line is all the numbers to the left of - 4 (including -4)

The matching graph is the B.

b. -10n ≥ -100

Divide both sides by - 10 => n ≤ 10

That is all the real numbers less or equal than 10.

In the real number line it is all the numbers to the left of 10, including 10.

So, the matching graph is the A.

c. 5x ≥ 20

Divide both sides by 5 => x ≥ 4

That is all the real numbers greater or equal to 4.

In the real number line it is all the numbers to the right of 4, including 4.

The matching graph is C.

4 0

3 years ago

Explain how probability can be used to help a sales person forecast future sales.

Naily [24]

Answer with explanation:

A salesperson can use probability to get an idea of his business as using probability he can estimate his sale of the next month as well, based on the present and previous months sales.

It can help him sort issues or errors he is facing in his business as he will get a complete idea of his business using probability.

Moreover, he can forecast future sales by using a technique which involves assigning percentages or weighting benchmarks in sales cycle, so that he can estimate the expected revenue generated.

For example:

A supermarket sales person can assign probabilities to benchmarks in sale cycle as providing needs analysis (25 % probability), adding new product (50%Probability) , Remove a product ( 75 % probability), closing sale (100% Probability) . If these probabilities are large, then forecast model can be objective.

_____________________________________________________

So just like that by assigning probabilities to benchmarks, a sales person can forecast future sales

6 0

2 years ago

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what equation is solved by the graphed systems of equations? Two linear equations that intersect at the point negative 1, negati

alexgriva [62]

Answer:

1. The equation is solved by the graphed systems of equations is:

Third option: 7x + 3 = x − 3

2. The solution to the system is:

Fourth option: (3,-1)

3. The graph of the system y = −2x + 3 and 2x + 4y = 8 is:

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

4. The solution to the system is:

Second option: Infinite solutions.

5. Bill will have read the same amount of books as Mandy in:

Fourth option: December

Step-by-step explanation:

Question 1. What equation is solved by the graphed systems of equations?

Two linear equations that intersect at the point (-1, -4)=(x,y)→x=-1, y=-4

a. 7x + 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x+3-x

6x+3=3

Subtracting 3 both sides of the equation:

6x+3-3=3-3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

b. 7x − 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x-3-x

6x-3=-3

Adding 3 both sides of the equation:

6x-3+3=-3+3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

c. 7x + 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x-3-x

6x+3=-3

Subtracting 3 both sides of the equation:

6x+3-3=-3-3

6x=-6

Dividing both sides of the equation by 6:

6x/6=-6/6

Dividing:

x=-1 equal to the intersection at x=-1, then this is the equation.

d. 7x − 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x+3-x

6x-3=3

Adding 3 both sides of the equation:

6x-3+3=3+3

6x=6

Dividing both sides of the equation by 6:

6x/6=6/6

Dividing:

x=1 different to the intersection at x=-1, then this is not the equation.

Question 2 (Multiple Choice Worth 2 points) (06.03) Solve the system 2x + 3y = 3 and 3x − 2y = 11 by using graph paper or graphing technology. What is the solution to the system?

The solution to the system is (3, -1) Fourth option

Please, see the attached graph.

Question 3 (Multiple Choice Worth 2 points) (06.03) What is the graph of the system y = −2x + 3 and 2x + 4y = 8?

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

Please, see the attached graph.

Question 4 (Multiple Choice Worth 2 points) (06.03) Solve the system y = 3x + 2 and 3y = 9x + 6 by using graph paper or graphing technology. What is the solution to the system?

Second option: Infinite solutions.

Please, see the attached graph.

Question 5 (Multiple Choice Worth 2 points) (06.03) At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up to Mandy. He tracks his book reading with a table on his door. Using his table below, what month will Bill have read the same amount of books as Mandy?

Bill

Month Books

May 4

June 8

July 12

August 16

September 20

October 24

November 28

December 32

Books read by Mandy: y=16+2x

Numbers of months since april: x

May: x=1→y=16+2(1)=16+2→y=18 different to 4 (books read by Bill)

June: x=2→y=16+2(2)=16+4→y=20 different to 8 (books read by Bill)

July: x=3→y=16+2(3)=16+6→y=22 different to 12 (books read by Bill)

September: x=5→y=16+2(5)=16+10→y=26 different to 20 (books read by Bill)

October: x=6→y=16+2(6)=16+12→y=28 different to 24 (books read by Bill)

November: x=7→y=16+2(7)=16+14→y=30 different to 28 (books read by Bill)

December: x=8→y=16+2(8)=16+16→y=32 equal to 32 (books read by Bill)

Answer. Fourth option: December

4 0

3 years ago

Describe how to transform the graph of g(x)= ln x into the graph of f(x)= ln (3-x) -2.

Strike441 [17]

Answer:

The graph of g(x) = ㏑x translated 3 units to the right and then reflected

about the y-axis and then translated 2 units down to form the graph of

f(x) = ㏑(3 - x) - 2

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) reflected across the x-axis, then the new

function g(x) = - f(x)

- If the function f(x) reflected across the y-axis, then the new

function g(x) = f(-x)

- If the function f(x) translated horizontally to the right

by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left

by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up

by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down

by k units, then the new function g(x) = f(x) – k

* lets solve the problem

∵ Graph of g(x) = ㏑x is transformed into graph of f(x) = ㏑(3 - x) - 2

- ㏑x becomes ㏑(3 - x)

∵ ㏑(3 - x) = ㏑(-x + 3)

- Take (-) as a common factor

∴ ㏑(-x + 3) = ㏑[-(x - 3)]

∵ x changed to x - 3

∴ The function g(x) translated 3 units to the right

∵ There is (-) out the bracket (x - 3) that means we change the sign

of x then we will reflect the function about the y-axis

∴ g(x) translated 3 units to the right and then reflected about the

y-axis

∵ g(x) changed to f(x) = ㏑(3 - x) - 2

∵ We subtract 2 from g(x) after horizontal translation and reflection

about y-axis

∴ We translate g(x) 2 units down

∴ g(x) translated 3 units to the right and then reflected about the

y-axis and then translated 2 units down

* The graph of g(x) = ㏑x translated 3 units to the right and then

reflected about the y-axis and then translated 2 units down to

form the graph of f(x) = ㏑(3 - x) - 2

7 0

3 years ago

Read 2 more answers