Answer:
A. Yes
B. –176 °C
Explanation:
A. Yes
B. Determination of the new temperature of the gas.
Let the initial pressure be P
From the question given above, the following data were obtained.
Initial pressure (P1) = P
Initial temperature (T1) = 19 °C
Final pressure (P2) = ⅓ P1 = ⅓P = P/3
Final temperature (T2) =?
Next, we shall convert 19 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T1) = 19 °C
Initial temperature (T1) = 19 °C + 273
Initial temperature (T1) = 292 K
Since the volume is constant, we can obtain the new temperature of the gas as illustrated below:
Initial pressure (P1) = P
Initial temperature (T1) = 292 K
Final pressure (P2) = P/3
Final temperature (T2) =?
P1/T1 = P2/T2
P/292 = P/3 /T2
P/292 = P/3T2
Cross multiply
P × 3T2 = 292 × P
Divide both side by P
3T2 = (292 × P)/P
3T2 = 292
Divide both side by 3
T2 = 292/3
T2 = 97.33 ≈ 97 K
Finally, we shall convert 97 K to celcius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 97
T(°C) = 97 – 273
T(°C) = –176 °C
Thus, the new temperature of the gas is –176 °C.
