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3 years ago

Which of the examples below is a chemical agent? Select one:

1 answer:

6 0

Chlorine, Anthax is a biological agent, and uranium is a radioactive agent, and dynamite is just a no. Chlorine is a chemical gas.

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How many moles of air are necessary for the combustion of 5.00 molmol of isooctane, assuming that air is 21.0% O2O2 by volume?

Annette [7]

Answer:

67.5 moles of O2

Explanation:

2 C 8 H 18 + 27 O 2 → 16 C O 2 + 18 H 2 O

According to the balanced chemical equation, in normal air % moles of iso-octane will require 67.5 moles of oxygen to combust completely...

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4 years ago

Metallic bonds are responsible for many properties of metals such as conductivity true or false?.

Alex17521 [72]

It is true that metallic bonds are responsible for many properties of metals such as conductivity.

Metallic bond is a type of chemical bond.

Metallic bond is formed between electrons and positively charged metal ions.

Substances with metallic bond conduct an electric current in liquid and solid state, because they have mobile electrons.

Most metals (for example sodium, calcium, iron, silver) have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

Metallic bond increace electrical and thermal conductivity.

More about metallic bond: brainly.com/question/21081009

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3 0

2 years ago

Please help<br>I need I badly or I'm going to fail<br>

Nimfa-mama [501]

Answer:

Its B

Explanation:

4 0

3 years ago

Read 2 more answers

A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce

spin [16.1K]

Explanation:

The given data is as follows.

Volume of lake = $15 \times 10^{6} m^{3}$ = $15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}$

Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = $5.6 \times 15 \times 10^{9} mg$

= $84 \times 10^{9}$ mg

= $84 \times 10^{3}$ kg

Flow rate of river is 50 $m^{3} sec^{-1}$

Volume of water in 1 day = $50 \times 10^{3} \times 86400 liter$

= $432 \times 10^{7}$ liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are $2.9792 \times 10^{10} mg$ or $2.9792 \times 10^{4} kg$