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ivolga24 [154]
3 years ago
5

The ions S-2, Cl-1, K+, Ca+2, Sc+3 have the same total number of electrons as the noble gas argon. How would you expect the radi

i of these ions to vary?
Chemistry
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

Cl^- <S^2-<Sc^3+ <Ca^2+<K^+

Explanation:

We know that ionic radius of ions decreases from right to left in the periodic table.  This is because, ionic radii decreases with increase in nuclear charge. This explains why; Sc^3+ <Ca^2+<K^+.

Secondly, even though Cl^- is isoelectronic with S^2-, the size of the nuclear charge in Cl^-  is larger compared to that of  S^2- . Hence Cl^-  is smaller than S^2- in ionic radius owing to increased nuclear attraction in Cl^-.

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