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ivolga24 [154]
3 years ago
5

The ions S-2, Cl-1, K+, Ca+2, Sc+3 have the same total number of electrons as the noble gas argon. How would you expect the radi

i of these ions to vary?
Chemistry
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

Cl^- <S^2-<Sc^3+ <Ca^2+<K^+

Explanation:

We know that ionic radius of ions decreases from right to left in the periodic table.  This is because, ionic radii decreases with increase in nuclear charge. This explains why; Sc^3+ <Ca^2+<K^+.

Secondly, even though Cl^- is isoelectronic with S^2-, the size of the nuclear charge in Cl^-  is larger compared to that of  S^2- . Hence Cl^-  is smaller than S^2- in ionic radius owing to increased nuclear attraction in Cl^-.

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If 0.60 L of a solution contains 6.6 g of NaBr, what is its molar concentration?
-BARSIC- [3]

Answer:

Molarity = moles ÷ liters

to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)

Na = 22.989769

Br = 79.904

molar mass of NaBr = 102.893769

6.6g ÷ 102.893769 = 0.064143826 moles of NaBr

0.064143826 moles ÷ 0.60 liters = 0.1069 molar concentration or 11 %

7 0
3 years ago
What is the Lewis Dot Diagram of gold?
ratelena [41]
Its structure is Au with one dot on top
6 0
3 years ago
Is the largest of Saturn's moons, Charon, larger than Mercury?​
vazorg [7]

Answer:

no, Charon is significantly smaller than Mercury

4 0
2 years ago
When 0.250 moles of KCl are added to 200.0 g of water in a constant pressure calorimeter a temperature change is observed. Given
777dan777 [17]

Explanation:

Upon dissolution of KCl heat is generated and temperature of the solution raises.

Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.

             17.24 kJ/mol \times 0.25 mol

                = 4.31 kJ

or,             = 4310 J      (as 1 kJ = 1000 J)

Mass of solution will be the sum of mass of water and mass of KCl.

       Mass of Solution = mass of water + (no. of moles of KCl × molar mass)

                                    = 200 g + (0.25 mol \times 54.5 g/mol)

                                    = 200 g + 13.625 g

                                    = 213.625 g

Relation between heat, mass and change in temperature is as follows.

                             Q = mC \Delta T

where,    C = specific heat of water = 4.184 J/g^{o}C

Therefore, putting the given values into the above formula as follows.

                     Q = mC \Delta T

            4310 J = 213.625 g \times 4.184 J/g^{o}C \times \Delta T      

              \Delta T = 4.82^{o}C

Thus, we can conclude that rise in temperature will be 4.82^{o}C.

6 0
3 years ago
Calculate the volume of 11 g of CO2 at NTP ?​
Kitty [74]
<h3>Answer:</h3>

5.6 Liters

<h3>Explanation:</h3>
  • N.T.P. refers to the standard temperature and pressure (S.T.P).

We need to know that;

  • One mole of a gas occupies a volume of 22.4 liters at N.T.P.

In this case;

We have 11 g of CO₂

But, 1 mole of CO₂ occupies 22.4 l at N.T.P.

1 mole of CO₂ = 44 g

Therefore;

44 g of CO₂ = 22.4 liters

What about 11 g ?

= (11 g × 22.4 l)÷ 44 g

= 5.6 l

Therefore, 11 g of CO₂ will occupy a volume of 5.6 liters at N.T.P.

8 0
3 years ago
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