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2 years ago

What is the complement of the supplement of 130 degrees?

Mathematics

1 answer:

Brut [27]2 years ago

5 0

Answer:

50°

Step-by-step explanation:

180° - 130° = 50°

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Answer with Step-by-step explanation:

We are given that an equation of curve

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$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

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Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

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Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

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The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

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$y=\frac{x}{\sqrt3}+4$

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What is the complement of the supplement of 130 degrees?​

What is the complement of the supplement of 130 degrees?