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WARRIOR [948]
2 years ago
9

I will give brainliest to whoever helps me with this question. Also, if you could please explain to me how you solved it I would

appreciate it! (this is Pythagorean Theorem if your wondering).

Mathematics
2 answers:
kolbaska11 [484]2 years ago
6 0
I will try to help okay i will send my friends to help
andreev551 [17]2 years ago
3 0
The answer should be 25 cm
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Variables are defined by what?
skad [1K]

Answer:

A variable is a quantity that may change within the context of a mathematical problem or experiment. ... The letters x, y, and z are common generic symbols used for variables. Sometimes, we will choose a letter that reminds us of the quantity it represents, such as t for time, v for voltage, or b for bacteria.

Step-by-step explanation:

thats true❤️

8 0
2 years ago
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How do you use equations to solve problems about area of rectangles, parallelograms, trapezoids, and triangles?
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3 years ago
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6 0
3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
2 years ago
A veterinarian is changing the diets of two animals, Simba and Cuddles. Simba currently consumes 1,520 Calories per day. That nu
kykrilka [37]

Answer:

6 days ; 2300 calories

Step-by-step explanation:

Given the following :

Current consumption :

Simba = 1520 calories per day

Increases by 130 calories per day : After d days ;

S(d) = 1520 + 130d

Where ; d = number of days

Cuddle = 3380 calories

Decreases by 180 calories each day; after d days ;

S(d) = 3380 - 180d

Pattern continues until they both consume same number of calories each day

S(d) = C(d)

1520 + 130d = 3380 - 180d

130d + 180d = 3380 - 1520

310d = 1860

d = 6

Number of calories they will be consuming them ;

Using : S(d) = 3380 - 180d

S(6) = 3380 - 180(6)

S = 3380 - 1080

S = 2300

They will be consuming 2300 calories by then.

8 0
3 years ago
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