It’s C. An MP3 file is an audio/video file, so only a media player would be able to play this
7 Basic Internal Component found in a computer tower:
1) Power Supply
2) Central Processing Unit (CPU)
3) Hard Disk Drive (HDD)
4) Motherboard
5) Video card
6) Random Access Memory (RAM)
7) Sound Card
*Expansion Card, Network Card, Bluetooth Card
<h2>Hello!</h2>
The answer is:
- CD
- DVD
- UDO
<h2>Why?</h2>
Optical disks are circular disks used as storage for binary data usually made of polycarbonate. The data is stored in the disc using a laser machine and accessed using a laser diode illuminating the data path in an optical disc drive.
CD: Compact Discs are the most basic optical disk used today, with only a capacity that goes from 0.7 GB (700 MB) to 0.84 GB (840 MB).
DVD: Digital Versatile Discs increase the storage up to 6 times compared with a CD, the capacity of DVDs optical disks goes from 4.7 GB (4700 MB) to about 17 GB(17000 MB).
UDO: Ultra Density Optical have high capacity storage that goes from 30 GB (30000 MB) to about 60 GB (6000 MB).
Have a nice day!
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
The answer is <span>0.693 . </span><span>When a switch is closed, completing an LR series circuit, the time needed for the current to reach one half its maximum value is 0.693
</span>e^(-t/T) = 0.5
<span>-t/T = ln(0.5) = -0.693 </span>
