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Alja [10]
3 years ago
13

Solve the right triangle, ΔABC, for the missing side and angles to the nearest tenth given sides a = 14.9 and b = 17.5.

Mathematics
1 answer:
givi [52]3 years ago
3 0

Answer:

C. A = 40.4 , B = 49.6 , c = 23

Step-by-step explanation:

First, we need to get the c using the pythagoras theorem;

c² = a²+b²

c² = 14.9²+17.5²

c²  = 222.01 + 306.25

c² = 528.26

c = 22.98

c ≈ 23

Using the sin rule;

a/Sin<A  = c/sin<C

14.9/sin<A = 23/sin90

14.9/sin<A = 23

sin<A = 14.9/23

sin <A = 0.6478

<A = arcsin(0.6478)

<A = 40.4degrees

Also, <A + <B + <C = 180

40.4 + <B + 90 = 180

<B = 180 - 130.4

<B = 49.6degrees

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Step-by-step explanation:

We know that DF = EF = 5 cm, since D and E are the midpoints of AC and AB, both of which are 10 cm in length.

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DE = \sqrt{5^{2} +5^{2}}=\sqrt{50}  = 7.07\\

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The sum of two numbers is 72 while the difference between the numbers is 25. the larger of the numbers is
7nadin3 [17]
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7 0
3 years ago
A<br> 9x - 40<br> B<br> 3x + 20<br> x = [?]
Mrrafil [7]

Answer:

x = 10

Step-by-step explanation:

9x - 40 = 3x + 20

<u>9</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>x</u> - 40 = <u>3x - 3x</u> + 20

6x - 40 = 20

6x <u>-</u><u> </u><u>40</u><u> </u><u>+</u><u> </u><u>40</u> = <u>20</u><u> </u><u>+</u><u> </u><u>40</u>

6x = 60

<u>6x</u><u> </u><u>/</u><u> </u><u>6</u> = <u>60</u><u> </u><u>/</u><u> </u><u>6</u>

x = 10

Now plug the x value in the equation to make the statement true that A is parallel to B.

9x - 40

<u>9</u><u>(</u><u>10</u><u>)</u> - 40

<u>90</u><u> </u><u>-</u><u> </u><u>40</u>

50

3x + 20

<u>3</u><u>(</u><u>10</u><u>)</u> + 20

<u>30</u><u> </u><u>+</u><u> </u><u>20</u>

50

Therefore, x = 10 making the statement true that A is parallel to B. Hope this helps and stay safe, happy, and healthy, thank you :) !!

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