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Finger [1]
3 years ago
8

What is the value of 7 over 3 divided by 5 over 6

Mathematics
2 answers:
rodikova [14]3 years ago
7 0

Answer:

7/3/5/6= 2.8

Step-by-step explanation:

kobusy [5.1K]3 years ago
3 0

Answer:

7/3 ÷ 5/6 = 2 4/5

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The formula for this.(sorry for the horrible graph it was hand drawn
ozzi

Answer:

y = 1/2x+5

Step-by-step explanation:

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3 years ago
For any positive numbers a, b, and d, with b ≠ 1, logb _____ = d • log^b a
e-lub [12.9K]

d \log_b a = \log_b a^d

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4 years ago
The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0
3 years ago
3(2x+5) = 2(3x+3). V.
zhenek [66]

Answer: no solution, try going into more detail. Sorry if this isnt helpful

Step-by-step explanation:

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3 years ago
Factorise x(x+z) -y(y+z)<br>Show calculation and please give correct answers.​
Alchen [17]

Answer:

(x-y)(x+y+z)

Step-by-step explanation:

x^{2} +xz-y^{2} -yz\\x^{2} -y^{2} +z(x-y)\\(x+y)(x-y)+z(x-y)\\(x-y)(x+y+z)\\

5 0
3 years ago
Read 2 more answers
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