Explanation:
(a)
The given data is:-
Energy = 2391 Calories
The conversion of calories to J is shown below as:-
1 calorie = 4.184 J
So,
Energy = 4.184 * 2391 J = 10003.944 J
Answer in four significant digits: - 
(b)
The conversion of calories to kJ is shown below as:-
1 calorie = 0.004184 kJ
So,
Energy = 0.004184 * 2391 kJ = 10.003944 kJ
Answer in four significant digits: - 
(c)
The conversion of calories to kWh is shown below as:-
1 calorie = 
kWh
So,
Energy = 
kWh = 0.002778873 kWh
Answer in four significant digits: - 
We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:
PV=nRT
We manipulate this equation to give us an expression which will correspond to density. We do as follows:
PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L
I’m sorry if I wasted your time but I think it’s alkali metals but I’m
Not sure
Answer:
CaO, CaF2, or CaCl2
Explanation:
In an ionic compound, the charges need to balance out. This is the only set of compounds that fits this criteria.
Hey there!
It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.
In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:
Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:
Thus, the density of the calcite sample will be:
This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL
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Regards!
