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Pachacha [2.7K]
3 years ago
13

Halp pls halppppppppppppppppppppppp

Chemistry
2 answers:
ira [324]3 years ago
8 0
Delete the cactus and the tree on the right for the first one and the third picture delete the lion moose Buffalo
Firdavs [7]3 years ago
8 0
I hope this helps
And I’m not really for sure about the tiger

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Radiation is a measure of average kinetic energy of particles in an object true or false ​
laila [671]

Answer:false

Explanation:

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3 years ago
In a solution of salt and water which compound is the solute?
ra1l [238]
Solute is what gets dissovled, in this case the salt, and the solVENT is whatever a material is dissolved into, in this case the water.
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4 years ago
What is chromatography​
Sergio [31]

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Chromatography is the method of separating mixture by using a solvent and filter paper..

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Read 2 more answers
Calcule el volumen de disolución de LiOH a 3.5 M, necesario para neutralizar una disolución de 25 ml de H2SO3 cuya densidad es d
Olin [163]

Respuesta:

0.11 L

Explicación:

Paso 1: Escribir la ecuación balanceada

2 LiOH + H₂SO₃ ⇒ Li₂SO₃ + H₂O

Paso 2: Calcular la masa de solución de H₂SO₃

25 mL de solución de H₂SO₃ tiene una denisdad de 1.03 g/mL.

25 mL × 1.03 g/mL = 28 g

Paso 3: Calcular la masa de H₂SO₃ en 26 g de Solución de H₂SO₃

La riqueza de H₂SO₃ es 60%, es decir, cada 100 g de solución hay 60 g de H₂SO₃.

26 g Sol × 60 g H₂SO₃/100 g Sol = 16 g H₂SO₃

Paso 4: Calcular los moles correspondientes a 16 g de H₂SO₃

La masa molar de H₂SO₃ es 82.07 g/mol.

16 g × 1 mol/82.07 g = 0.19 mol

Paso 5: Calcular los moles de LiOH que reaccionan con 0.19 moles de H₂SO₃

La relación molar de LiOH a H₂SO₃ es 2:1. Los moles de LiOH que reaccionan son 2/1 × 0.19 mol = 0.38 mol.

Paso 6: Calcular el volumen de solución de LiOH

0.38 moles de LiOH están en una solución 3.5 M. El volumen requerido es:

0.38 mol × 1 L/3.5 mol = 0.11 L

7 0
3 years ago
When 2,4-hexadiene is protonated, a resonance-stabilized secondary allylic carbocation is formed. Draw the curved arrow notation
NemiM [27]

Answer:see the image for the structure of the allylic carbocation

Explanation:

When 2,4-hexanediene is protonated at the 5-position as shown in the image, a carbonation is formed which can be stabilized by resonance. The positive charge can be found on carbon 4 or carbon 2 due to resonance of the allylic carbonation. The both structures are shown and electron movements were depicted using curved arrow notation in the structures shown in the image attached.

4 0
3 years ago
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