The balanced redox equation of the reaction is given below:
- I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻
The oxidizing agent is MnO₄ while the reducing agent is I⁻.
<h3>What are redox equations?</h3>
Redox equations are equations in which oxidation and reduction reactions occur together.
Redox reactions can take place in alkaline or acidic mediums.
The balanced redox equation of the reaction is given below:
- I⁻ + 2 MnO₄ + H₂O → IO₃⁻ + 2 MnO₂ + 2 OH⁻
The oxidizing agent is MnO₄ while the reducing agent is I⁻
In conclusion, a balanced redox equation is one in which the atoms and the change in oxidation state is equal on both sides of the reaction.
Learn more about redox equations at: brainly.com/question/27239694
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Answer:
Fe.
Explanation:
- The element which is oxidized is the element that losses electrons and its oxidation state be more positive.
- The element which is reduced is the element that gain electrons and its oxidation state be more negative.
<em> Fe goes from + 2 to +3, so, it is the element that is oxidized.</em>
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Answer:
K = K1×K2 = [CO2] [H2]⁴ / [H₂O]² [CH4]
Explanation:
Based on the reactions:
CH2 (g) + H2O(g) ⇄ CO (g) + 3H2 (g) K1
CO (g) + H2O (g) ⇄ CO2 (g)+H2(g) K2
The sum of both reactions is:
CH4 (g)+2H2O (g) ⇄ CO2(g)+4H2(g) And K of the reaction is: K = K1×K2
K is defined as the ratio between concentrations of products and reactans. Each compound must be elevated to its coefficient in the reaction. That is:
<h3>K = K1×K2 = [CO2] [H2]⁴ / [H₂O]² [CH4]</h3>
The charge of an e- is 1.60217657×10^-19 coulombs I.e. A very small number!
So 1 coulomb is much much bigger than the charge of an electron.
