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Dominik [7]
3 years ago
9

If ABCD is a rhombus and m<1 is 32° find m<3​

Mathematics
1 answer:
Allisa [31]3 years ago
3 0

Answer: CAN YOU MARK BRAINLIST PLZ

The two diagonals of a rhombus are perpendicular, therefore,  

m

∠

3

=

90

∘

The diagonals of a rhombus bisect the angles, therefore,  

m

∠

2

=

m

∠

1

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The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

According to the statement

We have a given that the maximum sum of the positive integers is 400.

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So, to find the value of the n we use the

A.P. Series'Summation formula

According to this,

S = n (n+1)/2

Here the value of s is 401

Then

S = n (n+1)/2

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By the use of the Discriminant formula the

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The negative value of n is neglected.

Therefore the value of n is 27.

So, The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

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