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2 years ago

15

The equation,y = 225x + 200, represents the cost,y, students must pay to play x sports, as long as the athlete's family has join

ed the boosters. Which statement is true?

1 answer:

Ira Lisetskai [31]2 years ago

5 0

Answer:

The answer is B I am on the time for learning format so It may differ but for me it's B

Step-by-step explanation:

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Chnstopher earned $142.20. He saved $24.50. He spent the rest on 2 new pairs

pogonyaev

Answer:

$58.25

Step-by-step explanation:

142.20 - 24.50 = 117.50

117.50 / 2 = 58.25

6 0

3 years ago

Read 2 more answers

The jar only contains nickels and dimes altogether there are 10 coins total of the value is 90 cents how many nickels and how ma

lilavasa [31]

Write a system of equations and solve.

x + y = 10
5x + 10y = 90

Multiply and combine equations

-5x - 5y = -50
5x + 10y = 90
------------------
5y = 40
y = 8
x = 2

There are 2 nickels and 8 dimes in the jar. Hope this helps! :)

3 0

2 years ago

Fill in the blanks below.

Dmitry_Shevchenko [17]

Answer:

a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em> </em> $m = \frac{y_{2} - y_{1} }{x_{2}-x_{1} }$ <em />

<em> </em> $m = \frac{-8-7 }{7-7 } = \frac{-15}{0} = infinite$ <em />

<em> m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em> </em> $m = \frac{y_{2} - y_{1} }{x_{2}-x_{1} }$ <em />

<em> </em> $m = \frac{7-7 }{9-(-6) } = \frac{0}{15} = 0$ <em />

<em>Slope of the line m =0</em>

6 0

3 years ago

Read and analyze the following then solve. <br>ASAP ASAP ASAP ASAP ASAP ASAP ASAP

Vaselesa [24]

☾☆☾☆☾☆☾☆☾☆☾☆☾☆☾☆☾☆☾☆☾☆☾

<h3>JOH-EUN OHUEYO!!</h3>

(GOOD AFTERNOON)

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$\frac{3}{6} \times \frac{1}{2} = \frac{1}{4}$

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$\frac{5}{7} \times \frac{3}{8} = \frac{15}{32}$

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$\frac{4}{8} \times \frac{1}{4} = \frac{1}{8}$

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$2 \frac{1}{2} \times 3 \frac{2}{5} = 8 \frac{1}{2}$

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$\frac{8}{14} \times \frac{1}{2} = \frac{2}{7}$

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$\frac{3}{4} \div \frac{1}{4} = 3$

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$1 \frac{2}{3} \div 2 \frac{3}{5} = \frac{25}{39}$

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$\frac{3}{9} \div \frac{2}{3} = \frac{1}{2}$

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$1 \frac{3}{7} \div 2 \frac{1}{6} = \frac{60}{91}$

➢

$2 \frac{4}{5} \div \frac{3}{10} = 9 \frac{1}{3}$

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3 years ago

Read 2 more answers

(-5b^3) (-3b^6)<br><br> Solve the equation

3241004551 [841]

Answer: 15b^9

Explanation:

-5*-3=15

b^3*b^6=b^9

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2 years ago