96.3 cm measured to the nearest tenth of a cm

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Fed [463]

Answer:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

Step-by-step explanation:

Factor constant terms:

$-2(-4sin(2\theta)+sin(\theta))=0$

Divide both sides by -2:

$sin(\theta)-4sin(2 \theta)=0$

Expand trigonometric functions using the fact:

$sin(2 \theta) =2 sin(\theta) cos(\theta)$

So:

$sin(\theta) -8sin(\theta)cos(\theta)=0$

Factor sin(x) and constant terms and multiply both sides by -1:

$sin(\theta) (8cos(\theta)-1)=0$

Split into two equations:

$(1)=8cos(\theta)-1=0\\\\(2)=sin(\theta)=0$

For (1)

Add 1 to both sides and divide both sides by 8:

$cos(\theta)=\frac{1}{8}$

Take the inverse cosine of both sides:

$\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z$

For (2)

Simply take the inverse sine of both sides

$\theta = k \pi, \hspace{3}k\in Z$

Therefore, the solutions are given by:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\ \theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

8 0

3 years ago

A manager needs to order company shirts for each employee. She was quoted the following rates. If she orders 75 shirts and passe

docker41 [41]

The answer is B.$7.47.

Let's first calculate how much in total 75 shirts cost:
- first 19 (less than 20) cost $10: 19 * $10 = $190
- the next 30 cost $8: 30 * $8 = $240
- the rest (26 = 75 - 19 - 30) cost $5: 26 * $5 = $130

So, in total 75 shirts cost $560:
19 * $10 + 30 * $8 + 21 * $5 = $190 + $240 + $130 = $560

Since 75 shirts are ordered, there must be 75 employees, so each employee must pay $7.47:
$565 ÷ 75 = $7.47

7 0

3 years ago

Read 2 more answers

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then what is the pr

andreyandreev [35.5K]

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500

Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.

We have to find the probability of observing at least one car during any 5 minute time interval.

Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.

Probability during 20 minutes interval=609/625

Probability during 1 minute interval=609/625*20

=609/12500

Probability during 5 minute interval=(609/12500)*5

=609/2500

Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.

Learn more about probability at brainly.com/question/24756209

#SPJ4

8 0

2 years ago

a homework assignment included 40 multiple choice questions Sabrina completed 65% of her assignment in David completed 4/5 of hi

bazaltina [42]

Answer:

6 or -6

Step-by-step explanation:

65% of 40=26
4/5 of 40=32
32-26=6
(or if you start with 26)
26-32=-6

7 0

2 years ago

Read 2 more answers

Malachy, Sushil and Fiona share some sweets in the ratio 7:1:1. Malachy gets 90 more sweets than Fiona. How many sweets does Sus

VashaNatasha [74]

Answer:

15

Step-by-step explanation:

Fiona (F) = Sushi (S)

Malachy (M) = 7 Fiona (F)

M = F + 90

F + 90 = 7F

6F = 90

F (Fiona) = 15

S (Sushi) = 15

check: Malachy (M) = 15 * 7 = 105

M-F = 105 - 15 = 90

3 0

3 years ago