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Sav [38]
3 years ago
10

Which graph is best to show categorical data?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0

Answer:

line graph

Step-by-step explanation:

thay show Categorical data mostly because it the better one

dexar [7]3 years ago
5 0

Answer:

Bar graphs, pie charts or circle graphs

Step-by-step explanation:

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The area of a regular octagon is 25 cm2 what is the area with the sides five times as large
marin [14]
125 cm2 is the answer
6 0
3 years ago
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Find the first four terms of the sequence using the recursive formula. ​
frozen [14]

Answer:

- 3, - 11, - 35, - 107

Step-by-step explanation:

Using the recursive formula with f(1) = - 3 , then

f(2) = - 2 + 3f(1) = - 2 + 3(- 3) = - 2 - 9 = - 11

f(3) = - 2 + 3f(2) = - 2 + 3(- 11) = - 2 - 33 = - 35

f(4) = - 2 + 3f(3) = - 2 + 3(- 35) = - 2 - 105 = - 107

Thus the first four terms are

- 3, - 11, - 35, - 107

3 0
3 years ago
the most a bowling ball can weigh is 7,258 grams. what is the most it can weigh when measured in pounds? explains plz
konstantin123 [22]
16 pounds because 7258 grams goes into 16.001
6 0
3 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
Can anyone explain tonme how to do this please?
Mars2501 [29]
C is right. She has partially completed the construction. Her next step is to use the arc markings to determine the radius to construct the circle.
4 0
3 years ago
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