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3 years ago

Which graph is best to show categorical data?

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

6 0

Answer:

line graph

Step-by-step explanation:

thay show Categorical data mostly because it the better one

dexar [7]3 years ago

5 0

Answer:

Bar graphs, pie charts or circle graphs

Step-by-step explanation:

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Which is equivalent to P(z ≥ 1.4)?

Bad White [126]

Answer:

1-P(z less than or equal to 1.4)

Step-by-step explanation:

To know what sentence is equivalent to the expression P(z ≥ 1.4), we just need to know the translation of the symbol '≥'

This symbol means that the expression in the left side is greater than or equal to the expression in the right side, so we can translate this symbol as 'greater than or equal to'.

As P means a probability, we can also shift the symbol from 'greater than or equal to' to 'less than or equal to' if we make 1 minus the probability, so the expression P(z ≥ 1.4) is equivalent to 1 - P(z ≤ 1.4), and this second expression can be translated as 1-P(z less than or equal to 1.4)

3 0

3 years ago

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What is 3.69÷0.3 please provide the answer

gizmo_the_mogwai [7]

Answer:

12.3

Step-by-step explanation:

7 0

3 years ago

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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.

koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

Revenue is Q₂ < $7,500 < Q₃

The sales for the week is better than 72.91% of all sales

The performance for the week for Bridge Road

Revenue; Q₂ < $7,100 < Q₃

The sale for the week is better than 59.87% of all sales

(b) The mean is $3611

The median is $3,600

The standard deviation is $3250

The Interquartile range is $6075

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

$\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]$

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

$Z = \dfrac{x - \mu }{\sigma }$

$Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193$

From the Z-Table, we have;

The percentile= 0.7291

Therefore, the sale for the week for Park Street is better than 72.91% of all the sales

Park Street revenue;

The z-score is given as follows;

$Z = \dfrac{7500 - 6611}{3580} \approx 0.25$

From the Z-Table, we have;

The percentile = 0.5987

Therefore, the sale for the week is better than 59.87 % of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

The new mean = $3,611

The new median = 6600 - 3000 = 3600

The new median = $3,600

The standard deviation and the interquartile range remain the same, therefore, we have;

The standard deviation = $3,580

The interquartile range = 9675 - 3600 = 6075

The interquartile range = 6075

Learn more here:

brainly.com/question/21133077

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5 0

2 years ago

What are the zeros for each function ? f(x) = 2(x+1)(x-3)(x-1) ^2 (squared)

Setler79 [48]

If you do 5*the ratio of ur mom then u will get Y which times ur dads ding dong get u f(x)= 758984327934792379427893.

4 0

2 years ago

In a research laboratory, a scientist measures the mass of a 1-carat diamond and finds it to be 200 milligrams, measured to the

vlada-n [284]

Answer:

$D=3.5\ gr/cm^3$

Step-by-step explanation:

Density

The density of an object of mass m and volume V is given by

$\displaystyle D=\frac{m}{V}$

It can be expressed in common units like $gr/lt, Kg/m^3, gr/cm^3$ or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

$m=200\ mg = 0.2\ gr$

$V=0.057\ cm^3$

Thus, the measured density is

$\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}$

$\boxed{D=3.5\ gr/cm^3}$

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

6 0

3 years ago