Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Not sure if your the same person but I had already done the work for this problem....
John's function : y = 3.5x - 4
Penny's function : y = 3x + 4
C. John's function has a greater rate of change, because 3.5 > 3
Answer:
6π
Step-by-step explanation:
The period indicates after which time the sine wave repeats.
You divide 2π by the factor in front of your function variable. This is 1/3 for your function.
So 2π/(1/3) = 6π
This is the simplest way I could explain that complex question.