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2 years ago

Solve for x please... it's for a test and it's really hard

Mathematics

2 answers:

trasher [3.6K]2 years ago

6 0

X= -10 hope this helped

LUCKY_DIMON [66]2 years ago

3 0

The answer is x=-10 hope this is right

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(7)/(3) of it is 5 (5)/(6)

slava [35]

let's firstly convert the mixed fraction to improper fraction and then take it from there, keeping in mind that the whole is "x".

$\stackrel{mixed}{5\frac{5}{6}}\implies \cfrac{5\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{35}{6}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{3}x~~ = ~~5\frac{5}{6}\implies \cfrac{7}{3}x~~ = ~~\cfrac{35}{6}\implies 42x=105\implies x=\cfrac{105}{42} \\\\\\ x=\cfrac{21\cdot 5}{21\cdot 2}\implies x=\cfrac{21}{21}\cdot \cfrac{5}{2}\implies x=1\cdot \cfrac{5}{2}\implies x=2\frac{1}{2}$

7 0

2 years ago

PLZZ HELP

Digiron [165]

54 because there are 12 inches in a foot 12 divided by 3 is 4 and 6 divided by 3 is 2. Add the 2 and 4 and multiply that by 9

4 0

2 years ago

Write an expression for the area of the shaded region in its simplest form. Show all of your steps.

patriot [66]

The area of the shaded region will be the area of the rectangle minus the area of the white square inside of it:

((x+10)(2x+5)) - ((x+1)(x+1))

First, FOIL both of the areas separately:

(2x^2 + 5x + 20x + 50) - (x^2 + x + x + 1)

Simplify within the parentheses by adding like terms:

(2x^2 + 25x + 50) - (x^2 + 2x + 1)

Now, subtract one equation from the other:

2x^2 + 25x + 50
-x^2 - 2x - 1
= x^2 + 23x + 49

This will be the equation for the area.

3 0

3 years ago

need help with this problem drop down1: 6, 10drop down2: 6, 10drop down3: less than (<), greater than (>), less than or eq

Kryger [21]

From the information given,

x represents number of small boxes while y represents number of large boxes.

If each small box can hold 6 books and each large box can hold 10 books, it means that the expression for the number of books that x small boxes and y large boxes can hold is

6x + 10y

If James can pack up to 110 books, it means that the number of books that he can pack is less than or equal to 110. The inequality representing this scenario is

6x + 10y ≤ 110

10y ≤ - 6x + 110

Dividing both sides of the equation by 10, we have

y ≤ - 6x/10 + 110/10

y ≤ - 3x/5 + 11

The graph is shown below

The inequality that represents this sitaution is 6x + 10y ≤ 110

The graph of the inequality wil have solid boundary at y = - 3x/5 + 11

and will be shaded below the line.

3 0

1 year ago

Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5

Minchanka [31]

Answer:

J (6,2) K (2,2)

Step-by-step explanation:

Now distance of AB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 8 units

CB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 6 units by using same formula

Now AB/CB must equal to GH/HJ as rectangles are similar

GH = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 4 units

8/6 = 4/HJ

So,

HJ = 3 units

Now if we see the coordinates given carefully, it is obvious that two perpendicular lines lie perfectly parallel to x and y coordinates in rectangle ABCD. A is (-7,-2) and B is (1,-2) which means distance along y-axis doesn't change. Similarly for C (1,-8) and D (-7,-8), one can see that distance between y-axis doesn't change. So lines AB and CD of rectangle are parallel with x and AD and BC are parallel with y-axis.

In rectangle GHJK one can see that in given coordinates, G(2,5) and H(6,5), y coordinate is same so it is parallel to x axis. Now, HJ is perpendicular to GH so it must be parallel to y axis. It means if we know the lengths of sides we can easily determine unknown coordinates by simple addition and subtraction.

So, we know HJ = 3 units

J is (6,2) since HJ is parallel to y axis so distance on x axis will remain unchanged and length of line HJ will effect distance of y axis.

Similarly K is (2,2) for the same reason.

6 0

3 years ago