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SSSSS [86.1K]
2 years ago
14

Solve for x please... it's for a test and it's really hard

Mathematics
2 answers:
trasher [3.6K]2 years ago
6 0
X= -10 hope this helped
LUCKY_DIMON [66]2 years ago
3 0
The answer is x=-10 hope this is right
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ANSWER QUICK AND I WILL MAKE YOU BRAINLIEST
alekssr [168]

Answer:

The width of the window should be 7.6\ ft and the height of the window should be 3.8\ ft

Step-by-step explanation:

we know that

The circumference of a semicircle (window) is equal to

C=\pi r

we have that

C=12\ ft

\pi=3.14

substitute and solve for r

12=(3.14)r

r=12/3.14=3.8\ ft

so

the width of the window is equal to the diameter of the semicircle

so

The width of the window should be 3.8*2=7.6\ ft and the height of the window should be 3.8\ ft

4 0
3 years ago
Mr. and Mrs. Suralbo earned a net taxable income of P568,986. Find the income tax due.
Contact [7]

Answer:

$198,000

Step-by-step explanation:

Since Mr. and Mrs. Suralbo are married and filing jointly, they would fall into the tax slab of 35% as their taxable income ranges between $414,701 to $622,050.

Taxable income = $568,986

Tax rate = 35%

Income tax due = $568,000 * 35/100

= $198,000

Thus, the income tax due for Mr. and Mrs. Suralbo would be $198,000.

8 0
3 years ago
-3(x - 5) = 3x + 15
Travka [436]

Answer:

false

Step-by-step explanation:

because

-3(x-5)

-3x+15

6 0
3 years ago
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
Hitman42 [59]

Answer:

The 95% confidence interval = (98.225, 98.655)

Step-by-step explanation:

The formula for Confidence Interval =

Mean ± z × standard deviation/√n

Where Mean = 98.44°F

Standard deviation = 0.30°F

n = number of samples is 10

Because our number if samples is small, we use the t score confidence interval formula

Mean ± t × standard deviation/√n

Degrees of Freedom = n - 1

= 10 - 1 = 9

We find the t score of 95% confidence interval and degrees of freedom 9

= 2.262

Hence,

Confidence interval = 98.44 ± 2.262 × 0.30/√10

= 98.44 ± 0.214592162

Confidence Interval

98.44 - 0.214592162

= 98.225407838

≈ 98.225

98.44 + 0.214592162

= 98.654592162

≈ 98.655

The 95% confidence interval = (98.225, 98.655)

5 0
3 years ago
What is the initial value of the equation shown?
lapo4ka [179]

Answer:

-5

Step-by-step explanation:

The initial value would be the value when x=0.  Substituting 0 for x,

y = -2(0)-5

y = 0 - 5

y = -5

5 0
3 years ago
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