Answer:
Isosceles obtuse Triangle
Answer: The shaded area is 99.55 units squared.
Step-by-step explanation:
r = 3.2
Now, we can see that the sides of the square are equal to two times the diameter of the circles (or four times the radius of the circles), so the length of the sides of the square is:
L = 2*(2*3.2) = 12.8
The area of the square is A1 = L^2 = 12.8*12.8 = 163.84 units squared.
the shaded semicircle has a diameter of 4 times r (so the radius is 2 times r), and the area is equal to half the area of a circle:
A2 = (1/2)*pi*(2r)^2 = (1/2)*3.14*(6.4)^2 = 64.31 units squared.
And now we must subtract the area of the four smaller circles inside the square, the area of each one is:
A3 = pi*r^2 = 3.14*(3.2)^2 = 32.15 units squared.
Then the shaded area is:
A = A1 + A2 - 4*A3 = 163.84 + 64.31 - 4* 32.15 = 99.55 units squared.
Answer:
Step-by-step explanation:
well its 4.5-5.25= -0.75
Answer: 8r+5t
Step-by-step explanation:
8t + 6r - 3t + 2r
8t-3t= 5t
6r+2r=8r
= 8r+5t
Answer:
After 22 seconds the projectile reach its maximum height of 4,840 units
Step-by-step explanation:
we have
This is a vertical parabola downward (because the leading coefficient is negative)
The vertex is a maximum
Find out the coordinates of the vertex
Convert the quadratic equation in vertex form
Factor -10
Complete the square
Rewrite as perfect squares
The vertex is the point (22,4,840)
therefore
After 22 seconds the projectile reach its maximum height of 4,840 units
