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lapo4ka [179]
3 years ago
15

Select the correct answer.

Computers and Technology
1 answer:
dedylja [7]3 years ago
6 0

Answer:

D. MAN

Explanation:

A local area network (LAN) refers to a group of personal computers (PCs) or terminals that are located within the same general area and connected by a common network cable (communication circuit), so that they can exchange information from one node of the network to another. A local area network (LAN) is typically used in small or limited areas such as a set of rooms, a single building, school, hospital, or a set of well-connected buildings. Some of the network devices or equipments used in a local area network (LAN) includes an access point, personal computers, a switch, a router, printer, etc.

On the other hand, a metropolitan area network (MAN) is formed by an aggregation of multiple local area network (LAN) that are interconnected using backbone provided by an internet service provider (ISP). A metropolitan area network (MAN) spans for about 5 kilometers to 50 kilometers in size.

Basically, a metropolitan area network (MAN) spans across a geographic area such as a city and it's larger than a local area network (LAN) but significantly smaller than a wide area network (WAN).

In conclusion, the network type that the patrol services of a city's police department would most likely use is a metropolitan area network (MAN).

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If a system's instruction set consists of an 8-bit opcode, what is the maximum number of output signal lines required for the co
otez555 [7]

Answer:

D. 256

Explanation:

Given

Instructions = 8\ bit

Required

Determine the maximum number of output

To get the required value, we make use of the following:

Maximum = 2^n

Where n is the bits of the opcode.

i.e.

n = 8

Substitute 8 for n in Maximum = 2^n

Maximum = 2^8

Maximum = 256

<em>Hence, option D answers the question</em>

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3 years ago
File formats are linked to certain programs.<br><br> True<br> False
Lostsunrise [7]
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Consider the following statements regarding computer programs A - Variables can contain different values at different times.B -
jeka94

Answer:

The answer is: Only A is correct.

Explanation:

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6 0
3 years ago
Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
3 years ago
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