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babunello [35]
3 years ago
6

H(x)= -x^3-2x^2-3x+4; x=2

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:

h(2) = -18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = -x³ - 2x² - 3x + 4

x = 2

<u>Step 2: Evaluate</u>

  1. Substitute:                    h(2) = -(2)³ - 2(2)² - 3(2) + 4
  2. Exponents:                   h(2) = -8 - 2(4) - 3(2) + 4
  3. Multiply:                        h(2) = -8 - 8 - 6 + 4
  4. Subtract:                       h(2) = -16 - 6 + 4
  5. Subtract:                       h(2) = -22 + 4
  6. Add:                              h(2) = -18
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