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3 years ago

H(x)= -x^3-2x^2-3x+4; x=2

Mathematics

1 answer:

murzikaleks [220]3 years ago

4 0

Answer:

h(2) = -18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

h(x) = -x³ - 2x² - 3x + 4

x = 2

Step 2: Evaluate

Substitute: h(2) = -(2)³ - 2(2)² - 3(2) + 4
Exponents: h(2) = -8 - 2(4) - 3(2) + 4
Multiply: h(2) = -8 - 8 - 6 + 4
Subtract: h(2) = -16 - 6 + 4
Subtract: h(2) = -22 + 4
Add: h(2) = -18

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