Question

2) 13 years back my mother age was thrice my age and 2 years back she was twice my age then find a) The present age of my mother b) my present age​

Answer 1

Answer:

age of the Father is 46 and age of the son is 24

Step-by-step explanation:

13 years ago x was thrice y's age, or

(x - 13) = 3(y - 13); or

x - 3y = -26

2 years ago, x was twice y's age, or

(x - 2) = 2 (y - 2); or

x - 2y = -2

Subtracting equation 1 from 2:

x - 2y - (x - 3y) = -2 - (-26)

or y = 24