You are standing on the middle rung of a ladder.

Let f(x)=4x+7 and g(x)=3x-5. Find (g o f)(-4) A)-32 B)-61 C)-64 D)-9

olya-2409 [2.1K]

Answer for this question is -32

5 0

3 years ago

A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago

13 __ W=130 what is W 10 15 Points if you answer

11111nata11111 [884]

W=130

Step-by-step explanation:

the question giving says_W=130and if minus is crossing to the other side it becomes+

5 0

2 years ago

Simplify

guapka [62]

The first is a. you can rewrite it
$\sqrt{x^5} = \sqrt{x^2x^2x} = \sqrt{x^2}\sqrt{x^2}\sqrt{x} = xx\sqrt{x} = x^2\sqrt{x}$

the second is d. the only common factor between 20 and 40 that can be taken out is the 4 which becomes a 2, but inside the square roots there is still a 5 and 10, which cannot be combined

the third is c.
$\sqrt{36x} + \sqrt{100x} - \sqrt{25x} \\ 6\sqrt{x}+10\sqrt{x}-5\sqrt{x} \\ 11\sqrt{x}$

the fourth is d.
add 3 to both sides $\sqrt{2x} = 10$
then square both sides $2x=100$
then divide both sides by 2, x=50

3 0

3 years ago

Please help me with this homework

lianna [129]

Answer:

The third one

y+1=-2(x-3)

Step-by-step explanation:

Solve y+1=-2(x-3)

y+1=-2(x-3) becomes y=-2x+5

Then just graph it.

8 0

3 years ago