We need to define our outcomes and events.
Finding the probability<span> of each event occurring
separately, and then multiplying the probabilities is the step to <span>finding
the probability</span> of two
independent events that occur in
sequence.
</span>
<span>
To solve this problem, we take note of this:</span>
The roll of the two dice are denoted by the pair
(I, j) ∈ S={ (1, 1),(1, 2),..., (6,6) }
Each pair is an outcome. There are 36 pairs and each has
probability 1/36. The event “doubles” is { (1, 1),(2, 2)(6, 6) } has
probability p= 6/36 = 1/6. If we define ”doubles” as a successful roll, the
number of rolls N until we observe doubles is a geometric (p) random variable
and has expected value E[N] = 1/p = 6.
Answer:
y = 95° (being corresponding angle)
it is very easy.
you can also do
The answer is <span>one halfn − 16
</span>
Let the number be n.
<span>One half of a number is (1/2n)
</span><span>decreased by 16 is (-16)
</span><span>one half of a number decreased by 16 is
1/2n - 16
Or </span><span>one halfn − 16</span>
Answer:
9 and 11
Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.
n(n + 2) = 99
Solve for n.
n2 + 2n - 99 = 0
(n + 11)(n - 9) = 0 ⇒
Two solutions:
n = -11
n + 2 = -9
and
n = 9
n + 2 = 11
Test the answers.
