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Virty [35]
3 years ago
5

A record store owner assesses customers entering the store as high school age, college age,

Mathematics
1 answer:
Eva8 [605]3 years ago
3 0

Step-by-step explanation:

(a) P = (0.3)(0.2) + (0.5)(0.6) + (0.2)(0.8)

P = 0.52

(b) (0.5)(0.6) = 0.3

P = 0.3 / 0.52

P = 0.58

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Бx + 4y= 18 —бх+ бу = -18​
sertanlavr [38]

Answer:

x= 3

y = 0

Step-by-step explanation:

•Add the two equations to cancel out +6x and -6x

•Find the value of y

•Substitute the value of y into equation 1 to find the value of x.

Hope I was able to help you:)

7 0
3 years ago
A college student has 700$ in their account she spends $165 from the account on books and then deposits $190 in the account how
adell [148]

Hello,

I hope so far you and your family are staying safe and healthy!

We need to solve this step by step.

The college student has $700 in their account.  But then she spends $165 on books from that money. So we need to Subtract that.

700 - 165 =535

However, later on, she deposits $190 to the same account. So we need to take the remain we had and add it to the new amount.

535 + 190 = 725

Thus,

There are $725 in the account.

I wish you all the best!

~Gary

4 0
3 years ago
Help me with this please​
In-s [12.5K]

Answer:

8.125

Step-by-step explanation:

16.25*0.50=8.125

4 0
3 years ago
What is the sign of the product (-7)(-2)(-5)(1)? (5 points) ]
DIA [1.3K]
As a rule the product of an ODD number of NEGATIVE SIGNS is always NEGATIVE

An the product of an EVEN number of NEGATIVE SIGNS is always POSITIVE
Then the following statement is the right one:
Negative, because the product (-7)(-2) is positive, and the product (-5)(1) is negative and the product of a positive and a negative number is negative
4 0
3 years ago
You roll a die with the sample space S = {1, 2, 3, 4, 5, 6}. You define A as {1 ,4, 6}, B as {1, 3, 4, 5, 6}, C as {1, 5}, and D
Lilit [14]

Answer:

Step-by-step explanation:

Recall that two events A,B are called mutually exclusive if and only if A\cap B = \emptyset (their intersection is empty). They are exhaustive if they are mutually exclusive and their union is the sample space.

Based on this

a) Note that A\cap B = \{1,6\}, so they are not mutually exclusive nor exhaustive.

b) A\cap C = \{1\} so they are not mutually exclusive nor exhaustive.

c) A\cap D = \emptyset, so they are mutually exclusive. Note that A\cup D = \{1,2,3,4,5,6\}=S. Then they are exhaustive.

d) B\cap C = \{1,5\}, so they are not mutually exclusive nor exhaustive.

6 0
3 years ago
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