Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
-0.5
Step-by-step explanation:
36b+12b=-11-13
48b=-24
B=-24/48=-1/2
B=-0.5
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Answer:
313 ft
Step-by-step explanation:
If 12in = 12 ft
313in = x
= 313 ft

b - 10 = 7
Take 10 to the other side.

b = 17
Multiply by 4 to isolate b

b × 4 = 17 × 4
4 and 4 cancels out
b = 68