Answer:
1. Perpendicular
2. Isosceles
3. Never
Step-by-step explanation:
1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.
2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )
In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )
But, OA = OC because both are radius of same circle
So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC
⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.
3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius
O.99 is the answer to this problem
The other end point is 0,4
Multiply the number in the tens place of the bottom
number by the number in ones place of the top number. So
multiply the 1 by the 5, which makes 5. Multiply the number in
the tens place of the bottom number by the number in tens
place of the top number. Multiply 1 by 2, which equals 2.