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Dmitry_Shevchenko [17]
3 years ago
8

Lindsey is buying supplies for school. The list below shows what Lindsey bought and how much each item cost.

Mathematics
1 answer:
siniylev [52]3 years ago
3 0

Answer:

okie dokie

Step-by-step explanation:

Part A: it cost her $31.49 total.

Part B: she has $8.51 left over

Hop this helps :)

Have  a great day :)

brainliest? pls?

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At the market, 5 light bulbs cost $9. How much do 7 light bulbs cost?
Rudiy27
Hello!

To solve this, find the cost of a single light bulb first, by dividing 9 / 5.

9 / 5 ==> 1.80

One light bulb is $1.80

Now, multiply 1.80 by 7.

1.80 * 7 = 12.6

7 light bulbs cost $12.6

Hope this helps! ☺♥


6 0
4 years ago
Read 2 more answers
How can i differentiate this equation?
Dmitry_Shevchenko [17]

\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}


\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}

8 0
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Answer:

x = 4, y = 9.

Step-by-step explanation:

3x -2y = -6 and y = x+5

Substitute y = x + 5 in the first equation:

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x = -6 + 10

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So y = 4 + 5 = 9.

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