Question

The ball with a mass of 1.5 kilograms is tied to the end of

Answer 1

Solve the

potential energy at point B

PE = mgh

Where m is

the mass

G is the

acceleration due to gravity 9.8 m/s2

H is the height

PE = ( 1.5

kg) ( 9.8 m/s2) (0.5 m)

PE = 7.35 J

Solve the

velocity using the

KE = 0.5mv^2

Where ke is

the kinetic energy

M is the

mass

V is the

velocity

Since all

energy is converted to KE

So KE = PE

7.35 = 0.53(1.5)

v^2

V = 3.13 m/s

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Answer 2

Explanation:

It is given that,

Mass of the ball, m = 1.5 kg

The ball is pulled to a height of 0.5 meters and then released.

The potential energy at point B is given by :

$E_p=m\times g\times h$

$E_p=1.5\times 9.8\times 0.5$

$E_p=7.35\ J$

To find the velocity at point A, it is required to use the conservation of energy as :

$mgh=\dfrac{1}{2}mv^2$

$v=\sqrt{2gh}$

$v=\sqrt{2\times 9.8\times 0.5}$

v = 3.13 m/s

Hence, this is the required solution.