All categories

3 years ago

Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-6, 1); focus: (-6, 0)

Mathematics

1 answer:

GREYUIT [131]3 years ago

8 0

Answer: $(x+6)^2=-4(y-1)$

Step-by-step explanation:

Given

Vertex of the parabola $(-6,1)$

Focus of the parabola $(-6,0)$

As the x coordinate of vertex and focus is same and focus lie below the vertex, therefore the parabola is the type of

$(x+6)^2=-4a(y-1)$

distance between Vertex and focus is 1 unit

$\therefore a=1$

Parabola becomes

$\Rightarrow (x+6)^2=-4(y-1)$

You might be interested in

Will give BRAINLIEST!!!! Answer fast!!! Jude factored 27x^2 as (20x)(7x). Yasmin factored 27x^2 as (9)(3x^2). Which of them fact

julia-pushkina [17]

Hey there :)

27x² is what we are trying to factorise

When factorising, we do not add but we multiply

Jude factored : ( 20x )( 7x ) → This is wrong, since 20x × 7x = 140x²
Yasmin factored : ( 9 )( 3x² ) → This is right indeed as 9 × 3x² = 27x²

Yasmin is right

6 0

3 years ago

the amount of time a certain brand of light bulb lasts is normally distributed with a mean if 1800 hours and a standard deviatio

RUDIKE [14]

Answer:

340%

Step-by-step explanation:

4 0

3 years ago

Steph,andra,emily,and becca are planning a road trip from their hometown to san antonio

morpeh [17]

Answer:

a. Emily should begin her turn as the third driver at point (1, -0.5).

b. Emily's turn to drive end at point (-2.5, -3.75).

Step-by-step explanation:

Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:

Hometown

$H(x,y) = (8,6)$

San Antonio

$T(x,y) = (-6,-7)$

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:

Steph

$S(x,y) = H(x,y) + \frac{1}{4}\cdot [T(x,y)-H(x,y)]$ (1)

$S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]$

$S(x,y) = (8,6) +\frac{1}{4}\cdot (-14,-13)$

$S(x,y) = (4.5,2.75)$

Andra

$A(x,y) = H(x,y) + \frac{2}{4}\cdot [T(x,y)-H(x,y)]$ (2)

$A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]$

$A(x,y) = (8,6)+\frac{2}{4}\cdot (-14,-13)$

$A(x,y) =(1, -0.5)$

Emily

$E(x,y) = H(x,y) + \frac{3}{4}\cdot [T(x,y)-H(x,y)]$ (3)

$E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]$

$E(x,y) = (8,6)+\frac{3}{4}\cdot (-14,-13)$

$E(x,y) = (-2.5, -3.75)$

a. <em>If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver? </em>

Emily's beginning point is the Andra's stop point, that is, $A(x,y) =(1, -0.5)$ .

Emily should begin her turn as the third driver at point (1, -0.5).

b. <em>At what point does Emily's turn to drive end?</em>

Emily's turn to drive end at point (-2.5, -3.75).

7 0

3 years ago

Help!!! evaluate peicewise functions

aksik [14]

Answer:

Step-by-step explanation:

You choose the middle one because 3<(4)<10 makes sense where as the other ones don't when you plug in 4. Then you solve the equation which is x^2-7 and then you get 16-7 which is 9.

4 0

3 years ago

Cual es la historia de las funciones lineales ?

Oxana [17]

I don’t understand u sorry ;-;

4 0

4 years ago