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bija089 [108]
3 years ago
13

Which of the following values of r will result in a true statement when substituted into the given equation?

Mathematics
1 answer:
wariber [46]3 years ago
5 0
I think that it is A I guessed
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Michael is paid by the hour and gets overtime (OT) for every hour over 40.Last week he worked 52 hours. How many hours of OT did
aksik [14]

Answer:

12

Step-by-step explanation:

52 minus 40

6 0
3 years ago
The thrift store is selling their old DVDs. When the DVDs first came out, they sold for $19. They have now been marked down by 7
Luda [366]

Step-by-step explanation:

original price (100%) → $19

discounted price ((100-75)%) = (25%) → 25% x $19 = $4.75

8 0
3 years ago
Read 2 more answers
The pressure at sea level is 11 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of
Taya2010 [7]

Answer:

p(x) = 0.1x + 1

Step-by-step explanation:

Pressure at sea level = 1 atmosphere

Depth dove by Sydney = 23 meters

Pressure at a depth of 23 meters = 3.3 atmospheres

So,

Pressure at a depth of 23 meters = Pressure at sea level + k * Depth dove by Sydney

where k is  the diving rate constant

=> 3.3 = 1 + k(23)

=> 3.3 = 23k + 1

Subtracting 1 from both the sides, we get

3.3 - 1 = 23k + 1 -1

Cancelling out the +1 and -1 from the right side, we get

2.3 = 23k

=> 23k = 2.3

Dividing both sides by 23, we get

\frac{23k}{23} = \frac{2.3}{23}

Cancelling out the 23's from the top and bottom of the left side, we have

k = 0.1

Plugging in the value of k in the equation, we get

Pressure at a particular depth = Pressure at sea level + k * Depth dove by Sydney

p(x) = 1 + k(x)     [where p(x) is the pressure at a depth x]

=> p(x) = 1 + 0.1(x)

=> p(x) = 0.1x + 1

5 0
3 years ago
Find the area enclosed by the graphs of y=√(4-4x), y=√(4-x) and x-axis by integrating with respect to x and integrating with res
Sloan [31]

Answer:

(A) 2/3 [√(4-4x)]^3

(B) 2/3 [√(4-x)]^3

Step-by-step explanation:

Integrating the functions,

(A) Any function in square root is equal to or same as the function raised to the power of 1/2

To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2

Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.

Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.

Here, the denominator is 2, so you take the square root of the function, and raise the function to the power of 3

So the integral of Y = √[4-4x] is

2/3 [√(4-4x)]^3

(B) In like manner, the integral of

Y = √[4-x] is

2/3 [(√4-x)]^3

6 0
4 years ago
Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio
s344n2d4d5 [400]

Answer:

A)\frac{1}{1024},\frac{1}{4096}

B) \left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) \\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

Step-by-step explanation:

1) Incomplete question. So completing the several terms:\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}

We can realize this a Geometric sequence, with the ratio equal to:

q=\frac{1}{4}

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

6 0
3 years ago
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