1. A golf ball is hit at an angle of 40 degrees to the horizontal at a velocity of 24 m/s. Calculate the Viy.
1 answer:
Answer:
See the answers below
Explanation:
In order to solve these problems, we must decompose the magnitudes of the velocities on the x & y-axes, using the angles that are given. It is important for a better understanding to look at the attached image and understand how the angles are located relative to the horizontal axis.
1.
The horizontal component of the angle can be found with the cosine function. While the vertical component can be found using the sine function of the angle.
Viy = 24*sin (40)
Viy = 15.42 [m/s]
2.
The horizontal component of the angle can be found with the cosine function.
Vix = 24*cos(40)
Vix = 18.38 [m/s]
3.
Vix = 55*cos(25)
Vix = 49.84 [m/s]
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a) , 1.6 A
b) , 1.33 A
Explanation:
a)
In this situation, we have two resistors connected in series.
The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:
where
Therefore, the equivalent resistance is
Now we can use Ohm's Law to find the current flowing through the circuit:
where
V = 8 V is the voltage supplied by the battery
is the equivalent resistance of the circuit
Substituting,
The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.
b)
In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is
where:
Substituting, we find the equivalent resistance:
Now we can find the current through the circuit by using again Ohm's Law:
where
V = 8 V is the voltage supplied by the battery
is the equivalent resistance
Substituting,
And the three resistors are connected in series, therefore the current flowing through each resistor is the same, 1.33 A.
At t=0, the particle was at its equilibrium position. The time period is 32 seconds, so in 8 seconds, it will reach the extreme location once, and hence, in 8 seconds, it will cover a distance equivalent to its amplitude.
