1. A golf ball is hit at an angle of 40 degrees to the horizontal at a velocity of 24 m/s. Calculate the Viy.
1 answer:
Answer:
See the answers below
Explanation:
In order to solve these problems, we must decompose the magnitudes of the velocities on the x & y-axes, using the angles that are given. It is important for a better understanding to look at the attached image and understand how the angles are located relative to the horizontal axis.
1.
The horizontal component of the angle can be found with the cosine function. While the vertical component can be found using the sine function of the angle.
Viy = 24*sin (40)
Viy = 15.42 [m/s]
2.
The horizontal component of the angle can be found with the cosine function.
Vix = 24*cos(40)
Vix = 18.38 [m/s]
3.
Vix = 55*cos(25)
Vix = 49.84 [m/s]
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Answer:
Proton’s speed, a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s
Explanation:
Given;
initial speed of proton, u = 2.5 x 10⁵ m/s
initial potential, V = 1500 V
mass of proton = 1.67 x 10⁻²⁷ kg
Work done, W = eV= ΔK.E = ¹/₂mu²
eV = ¹/₂mu² (J)
where;
e is the charge of the proton in coulombs
V is the electric potential in volts
m is the mass of the proton in kg
u is the speed of the proton in m/s
Therefore, proton’s speed a short time later when it reaches a point of lower potential is 1.4 x 10⁵ m/s