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3 years ago

14

A mass of 3.53 kg is placed on a vertical spring. What is the spring constant, in N/m, of a mass-spring system with a frequency

of 0.58 Hz?

1 answer:

Vika [28.1K]3 years ago

8 0

Answer:hey man

Explanation:

shesh

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This graph represents the solubility for a solid soluble salt. Predict how would the solubility curve for a gas would compare gi

lys-0071 [83]

Took a a test and got it correct .... ——-The solubility curve for a gas would start higher and curve downwards as temperature increased

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4 years ago

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A roller coaster needs to climb a tall hill. How tall of a hill can it climb with an initial

iren [92.7K]

Answer:

h = 11.25m

Explanation:

mgh = 1/2mv2

gh = 1/2v2

10 x h = 1/2 x 15 x 15

20 x h = 225

h = 225/20

h = 11.25m

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4 years ago

For a certain ideal Carnot engine, the hot reservoir is 35°C higher than the cold reservoir. If this engine is to have an effici

lord [1]

Answer:

Temperature of the hot reservoir is 1540K

Explanation:

$E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35 (convert 35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation 1)20%=1-{T_c}/{T_h}$

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

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3 years ago

Objects with masses of 181 kg and 712 kg are separated by 0.442 m. A 72.6 kg mass is placed midway between them. 0.442 m b b 181

Semmy [17]

Answer:

The Force exerted by the two objects will be same and 4,401,189.49 × 10−11 N

Explanation:

Let m1 be the mass of the first object and m2 be the mass of the second object and the distance between them be d. Then

m1= 181kg

m2= 712 kg

d= 0.442 m

G is the gravitational Constant

According to Newtons Law Gravitational Force is given by

F=G m1 m2 /d²

F= 6.672 × 10−11 ×181×712/(0.442)²

F= 859,576.24 × 10−11/0.195364

F= 4,401,189.49 × 10−11 N

The Force exerted by the two masses on the third mass will be same and 4,401,189.49 × 10−11 N

5 0

3 years ago

A roller skater of 47kg moving with a velocity of 12 m/s to the east picks up a bag of 6.0 kg. What is the final velocity of the

WITCHER [35]

Answer:

v_f = 10.85 m/s

Explanation:

We will apply the law of conservation of momentum here:

$m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f}+m_{2}v_{2f}\\$

where,

m₁ = mass of roller skater = 47 kg

m₂ = mass of bag = 6 kg

v_1i = initial speed of roller skater = 12 m/s

v_2i = initial speed of the bag = 0 m/s

v_1f = final speed of the roller skater = ?

v_2f = final speed of the bag = ?

Both the bag and the skater will have same speed at the end because kater is carrying the bag:

v_1f = v_2f = v_f

Therefore, the equation will become:

$(47\ kg)(12\ m/s)+(6\ kg)(0\ m/s)=(47\ kg)(v_{f})+(5\ kg)(v_{f})\\564\ N.s = (47\ kg+5\ kg)(v_{f})\\v_{f} = \frac{564\ N.s}{52\ kg}\\$

<u>v_f = 10.85 m/s</u>

8 0

3 years ago