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insens350 [35]
3 years ago
7

What is the answer to my question

Physics
2 answers:
Andrew [12]3 years ago
7 0
Well that depends...what is your question?
trapecia [35]3 years ago
5 0
74, you have to subtract the onion rings first. 
You can also do it this way: November+potato-right sock= cheese pumpkin.
That would equal 54

I hope I helped:)
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How does the water cycle transport energy and matter
natali 33 [55]

Explanation:

Water evaporates from the surface of the earth and through the leaves of the plants and trees by absorbing the heat energy from the surrounding.

This water then converts into vapour and goes up into the atmosphere where the temperature is low in the troposphere and condenses to form the clouds. During the cloud formation the heat form the vapour is absorbed in the troposphere.

These clouds when get saturated then fall in the form of precipitation of water, snow etc. Replenishing back the water of the earth.

7 0
3 years ago
IM DESPERATE PLS HELP ME I DONT UNDERSTAND THIS! PLEASE PLEASE PLEASE ANSWER BACK
OlgaM077 [116]

Answer:

The speed with which the man flies forward is 5.5 m/s

Explanation:

The mass of the man = 100 kg

The mass of the scooter = 10 kg

The speed with which the man was traveling on the scooter = 5 m/s

The speed of the scooter after it hits the rock = 0 m/s

Let v represent the speed with which the man flies forward

The formula for momentum, P, is P = Mass × Velocity

The conservation of linear momentum principle is, the total initial momentum = The total final momentum, therefore, we have;

The total initial momentum = (100 kg + 10 kg) × 5 m/s = 550 kg·m/s

The total final momentum = 100 kg × v + 10 kg × 0 m/s = 100 kg × v

When the momentum is conserved, we have;

550 kg·m/s = 100 kg × v

∴ v = 550 kg·m/s/(100 kg) = 5.5 m/s.

The speed with which the man flies forward = v = 5.5 m/s

8 0
3 years ago
The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh
Aliun [14]

Answer:

The value is      A   = 39315 \  m^2

Explanation:

From the question we are told that

    The velocity which the rover is suppose to land with is  v  =  1 \ m/s

    The  mass of the rover and the parachute is  m  =  2270 \ kg

     The  drag coefficient is  C__{D}}  =  0.5

      The atmospheric density of Earth  is  \rho =  1.2 \  kg/m^3

     The acceleration due to gravity in Mars is  g_m  =  3.689 \  m/s^2

     

Generally the Mars  atmosphere density is mathematically represented as

          \rho_m  =  0.71 *  \rho

=>        \rho_m  =  0.71 *  1.2

=>        \rho_m  = 0.852 \  kg/m^3

Generally the drag force on the rover and the parachute  is mathematically represented as

          F__{D}} =  m  *  g_{m}

=>       F__{D}} =  2270   *  3.689  

=>       F__{D}} =  8374 \ N  

Gnerally this drag force is mathematically represented as

         F__{D}} =   C__{D}} *  A *  \frac{\rho_m * v^2 }{2}

Here A is the frontal area

So  

         A   =  \frac{2 *  F__D }{ C__D}  *  \rho_m  * v^2   }

=>       A   =  \frac{2 * 8374 }{ 0.5 *  0.852    *  1 ^2   }

=>       A   = 39315 \  m^2

8 0
3 years ago
OThy look jump mo I’ll I’ll
madreJ [45]
I have no idea what this means but I hope you are having a lovely day and that life treats you wonderfully because everyone deserves happiness. I hope you reach your goals that you’re pursuing. Have a nice day :)
6 0
3 years ago
An accessory such as a coupling that performs a mechanical rather than an electrical function is called?
Assoli18 [71]
Fitting is the answer
5 0
3 years ago
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