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2 years ago

Kinetic friction is affected by the weight of the object. TrueFalse

Physics

2 answers:

monitta2 years ago

7 0

Answer:

The answer is True. Friction is indeed affected by weight.

Explanation:

hjlf2 years ago

6 0

Answer;

The above statement is True

Kinetic friction is affected by the weight of the object.

<h3><u>Explanation;</u></h3>

Kinetic friction is a force that acts between moving surfaces. An object that is in motion over a surface experiences a force in the opposite direction to the direction of movement.
The equation for kinetic friction is given by the formula;

F= coefficient of friction * Normal force.

Normal force is the force of the table pushing back on the block and can be calculated by formula;

F = mass* acceleration due to gravity.

Therefore, the weight of an object determines its kinetic friction.

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. There are fewer organisms at the highest trophic levels, because

Amiraneli [1.4K]

Answer:

Because there is less energy at higher trophic levels

Explanation:

In a food chain that shows the feeding levels of organisms in an ecosystem, energy decreases as you move from the lowest trophic level to the highest trophic level.
The lowest trophic level consists of producers which have the highest energy as they trap energy directly from the sunlight.
The energy is lost from one trophic level to the next up to the highest trophic level which has the lowest energy.
Therefore, organisms at the highest trophic level are fewer in number but large in size.

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2 years ago

Two identical mandolin strings under 200 N of tension are sounding tones with frequencies of 590 Hz. The peg of one string slips

Slav-nsk [51]

To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as

$f = \frac{v}{\lambda}$

Then the relation between two different frequencies with same wavelength would be

$\frac{f'}{f} = \frac{v'/\wavelength}{v/\wavelength}$

$\frac{f'}{f} = \frac{v'}{v}$

The beat frequency heard when the two strings are sounded simultaneously is

$f_{beat} = f-f'$

$f_{beat} = f(1-\frac{f'}{f})$

$f_{beat} = f(1-\frac{v'}{v})$

We have the velocity of the transverse waves in stretched string as

$v = \sqrt{\frac{T}{\mu}}$

$v = \sqrt{\frac{200N}{\mu}}$

And,

$v' = \sqrt{\frac{196N}{\mu}}$

Therefore the relation between the two is,

$\frac{v'}{v} = \sqrt{\frac{192}{200}}$

$\frac{v'}{v} = \sqrt{0.96}$

Finally substituting this value at the frequency beat equation we have

$f_{beat} = 590(1-\sqrt{0-96})$

$f_{beat} = 11.92Hz$

Therefore the beats per second are 11.92Hz

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2 years ago

Middle adulthood marks the time period in which some adults face the fabled midlife crisis. What exactly is that? Do you think y

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2 years ago

What is the smallest accurate measurement that can be made with an instrument?

vovangra [49]

Dependent on what you are measuring and what took you are using. Please be more specific.

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3 years ago

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Dvinal [7]

Answer:

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