
(a) R2, R3 are parallel and series with R1
(b) R1, R2 and R3 are in parallel
Explanation:

(a)



Ra and R1 is in series
And there total will be R

(b)


The radius of its orbit, measured from Earth's center, will be 1.44 × 10⁷ mm.
<h3>What is Newton's law of gravitation?</h3>
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Given data in problem is;
The mass of Earth is, 
Gravitational constant, G =6.674 × 10⁻¹¹ N m₂/kg²
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

The centripetal force due to rotation of the satellite;

The centripetal and the gravitational force are equal;
![\rm F_g = F_c \\\\ \frac{Gm_sm_e}{r^2} = \frac{m_s v^2}{r} \\\\ r = G \frac{m_E }{v^2 } \\\\ r = G \frac{m_E }{(r \omega )^2 } \\\\ r = \sqrt[3]{\frac{Gm_E}{\omega^2}} \\\\ r = \sqrt[3]{\frac{6.67 \times 10^{-11}(5.98 \times 10^{24})}{(3.63 \times 10^{-4})^2}} \\\\ r = 1.44 \times 10^7 \ mm](https://tex.z-dn.net/?f=%5Crm%20F_g%20%3D%20F_c%20%20%5C%5C%5C%5C%20%20%5Cfrac%7BGm_sm_e%7D%7Br%5E2%7D%20%3D%20%20%5Cfrac%7Bm_s%20v%5E2%7D%7Br%7D%20%5C%5C%5C%5C%20r%20%3D%20G%20%5Cfrac%7Bm_E%20%7D%7Bv%5E2%20%7D%20%5C%5C%5C%5C%20r%20%3D%20G%20%5Cfrac%7Bm_E%20%7D%7B%28r%20%5Comega%20%29%5E2%20%7D%20%5C%5C%5C%5C%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BGm_E%7D%7B%5Comega%5E2%7D%7D%20%5C%5C%5C%5C%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%285.98%20%5Ctimes%2010%5E%7B24%7D%29%7D%7B%283.63%20%5Ctimes%2010%5E%7B-4%7D%29%5E2%7D%7D%20%5C%5C%5C%5C%20r%20%3D%201.44%20%5Ctimes%2010%5E7%20%20%20%5C%20mm)
Hence, the radius of its orbit measured from Earth's center will be 1.44 × 10⁷ mm.
To learn more about Newton's law of gravitation, refer to the link.
brainly.com/question/9699135.
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Answer:
Work done is 882000joule.
power is 29400watt.
Explanation:
given,
Mass(m)=500kg
Acceleration due to gravity(g)=9.8m/s²
Height(h)=6m
Time taken(t)=30s
Workdone=?
Power=?
now,
workdone=force*displaxement
= m*g*h
=500*9.8*6
=8,82,000joule
so, the work done by the man is 8,82,000joule.
then,
power=workdone/time taken
=8,82,000/30
=29,400watt
so, the required power to lift a load is 29,400watt.
The conductor is the metal wire inside or encased in the insulator, which as stated covers or insulates the conductor.